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3 years ago

Please help asap!!! !!!!....!!

Mathematics

1 answer:

bazaltina [42]3 years ago

4 0

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Pls help me i need help fast

Alona [7]

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40%

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30p Add up the total number of plants

12L we can see that lettuce is equal to 12

12/30 =0.4 or 40%

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4 years ago

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AleksandrR [38]

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3 years ago

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Find an equation of the sphere with center s23, 2, 5d and radius 4. What is the intersection of this sphere with the yz-plane?

spayn [35]

Answer:

Equation: $(x+3)^2+(y-2)^2+(z-5)^2=16$

Intersection: $(y-2)^2+(z-5)^2=7$

Step-by-step explanation:

We are asked to write an equation of the sphere with center center $(-3,2,5)$ and radius 4.

We know that equation of a sphere with radius 'r' and center at $(h,k,l)$ is in form:

$(x-h)^2+(y-k)^2+(z-l)^2=r^2$

Since center of the given sphere is at point $(-3,2,5)$ , so we will substitute $h=-3$ , $k=2$ , $l=5$ and $r=4$ in above equation as:

$(x-(-3))^2+(y-2)^2+(z-5)^2=4^2$

$(x+3)^2+(y-2)^2+(z-5)^2=16$

Therefore, our required equation would be $(x+3)^2+(y-2)^2+(z-5)^2=16$ .

To find the intersection of our sphere with the yz-plane, we will substitute $x=0$ in our equation as:

$(0+3)^2+(y-2)^2+(z-5)^2=16$

$9+(y-2)^2+(z-5)^2=16$

$9-9+(y-2)^2+(z-5)^2=16-9$

$(y-2)^2+(z-5)^2=7$

Therefore, the intersection of the given sphere with the yz-plane would be $(y-2)^2+(z-5)^2=7$ .

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3 years ago

10th term of 4, 7, 10, 13........ (Please enter number only) Hint Use a+(n-1)d

monitta

Answer:

Step-by-step explanation:

a + (n-1)d where a = first term; n = which number we want; d = common difference.

=> 4 + (10 - 1)3

=> 4 + (9)*3

=> 4 + 27

=> 31

4 0

3 years ago