Answer:
as no. of protons is equals to the no. of electrons so, it is a neutral atom.
but, as Atomic No. = Mass No. - No. of neutrons
Atomic No. = No. of protons = 18
so, Mass No. = Atomic No. + No. of Neutrons= 18 + 20 = 38
so, correct option is C.
Explanation:
Ionic solids have high melting points and are rather hard. ... Covalent solids comprise two- or three-dimensional networks of atoms held together by covalent bonds; they tend to be very hard and have high melting points
Explanation:
Since, the given reaction is as follows.

Initial: 36.1 atm 0 0
Change: 2x x x
Equilibrium: (36.1 - 2x) x x
Now, expression for
of this reaction is as follows.
![K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20%5Cfrac%7B%5BN_%7B2%7D%5D%5BO_%7B2%7D%5D%7D%7B%5BNO%5D%5E%7B2%7D%7D)
As the initial pressure of NO is 36.1 atm. Hence, partial pressure of
at equilibrium will be calculated as follows.
![K_{p} = \frac{[N_{2}][O_{2}]}{[NO]^{2}}](https://tex.z-dn.net/?f=K_%7Bp%7D%20%3D%20%5Cfrac%7B%5BN_%7B2%7D%5D%5BO_%7B2%7D%5D%7D%7B%5BNO%5D%5E%7B2%7D%7D)
x = 18.1 atm
Thus, we can conclude that partial pressure of
at equilibrium is 18.1 atm.
Answer:
The value of the equilibrium constant (K) remains the same.
Explanation:
A state of dynamic equilibrium is said to have been achieved in a reaction system when the rate of forward reaction equals the rate of reverse reaction.
At equilibrium, doubling the initial concentration of reactants have no effect on the equilibrium constant K. The equilibrium will rather shift to the left or right as required in order to annul the constraint.
Answer:
The product is 1-methylcyclopentanol
Explanation:
The acid-catalyzed hydration of alkenes involves the addition of a water molecule to a C=C double bond.
H₂O + C=C ⟶ H-C-C-OH
An H atom adds to one of the C atoms, and an OH group adds to the other
This reaction follows Markovnikov’s rule — the H adds to the C atom that has more hydrogen atoms, and the OH adds to the more substituted carbon.
The steps of the mechanism are:
- The aqueous sulfuric acid generates hydronium ions
- The nucleophilic π electrons attack an H atom on the hydronium ion, forming a carbocation on the more substituted C atom.
- The lone pair electrons on a water molecule attack the carbocation , forming an oxonium ion.
- Another water molecule removes the extra proton.
The product is the alcohol with the OH group on the more substituted carbon — 1-methylcyclopentanol.