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AURORKA [14]
2 years ago
14

According to Le Chatelier's principle, what happens to the equilibrium constant (K) when the concentration of the reactants is d

oubled? The value of the equilibrium constant (K) is doubled. The value of the equilibrium constant (K) is halved. The value of the equilibrium constant (K) remains the same. The value of the equilibrium constant (K) changes unpredictably.
Chemistry
2 answers:
slavikrds [6]2 years ago
5 0

Answer:

The value of the equilibrium constant (K) remains the same.

Explanation:

A state of dynamic equilibrium is said to have been achieved in a reaction system when the rate of forward reaction equals the rate of reverse reaction.

At equilibrium, doubling the initial concentration of reactants have no effect on the equilibrium constant K. The equilibrium will rather shift to the left or right as required in order to annul the constraint.

a_sh-v [17]2 years ago
4 0

Answer:

C

Explanation:

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For each solution, determine the p-values for each ion indicated. A solution that is 0.493 M in NaCl and 0.314 M in NH 4 Cl .
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Complete Question:

Ions to calculate the p-values: Na⁺, Cl⁻, and NH₄⁺

Answer:

pNa = 0.307

pCl = 0.093

pNH₄ = 0.503

Explanation:

The p-value is calculated by the antilog of the concentration of the substance of interest. For example, pH = -log[H⁺]. Thus, first, let's find the ions concentration.

Both substances are salts that solubilize completely, thus, by the solution reactions:

NaCl → Na⁺ + Cl⁻

NH₄Cl → NH₄⁺ + Cl⁻

So, for both reactions the stoichiometry is 1:1:1 and the concentration of the ions is equal to the concentration of the salts.

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