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AURORKA [14]
2 years ago
14

According to Le Chatelier's principle, what happens to the equilibrium constant (K) when the concentration of the reactants is d

oubled? The value of the equilibrium constant (K) is doubled. The value of the equilibrium constant (K) is halved. The value of the equilibrium constant (K) remains the same. The value of the equilibrium constant (K) changes unpredictably.
Chemistry
2 answers:
slavikrds [6]2 years ago
5 0

Answer:

The value of the equilibrium constant (K) remains the same.

Explanation:

A state of dynamic equilibrium is said to have been achieved in a reaction system when the rate of forward reaction equals the rate of reverse reaction.

At equilibrium, doubling the initial concentration of reactants have no effect on the equilibrium constant K. The equilibrium will rather shift to the left or right as required in order to annul the constraint.

a_sh-v [17]2 years ago
4 0

Answer:

C

Explanation:

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consider a 1000-ml graduated cylinder with marks every 100 ml. a student records the volume of liquid in the cylinder as 750 ml.
Ludmilka [50]

Answer:

Explanation:

The 1000-ml graduated cylinder with marks every 100 ml has least count of 100 ml . It means it can not measure a volume less than 100 ml . It can also measure volume in the integral multiple of 100 ml like 200 ml , 300 ml , 400 ml etc perfectly .  All these have significant figure of one .

It can not measure volume like 150 , 250 , 255 , 760 etc because these measurements are not the integral multiple of 100 . 750 is not a integral multiple of 100 so it can not measure volume of 750 ml.

4 0
3 years ago
Calculate the molar solubility of ca(io3)2 in each solution below. the ksp of calcium iodate is7.1 × 10−7.
e-lub [12.9K]
In order to find the answer, use an ICE chart:

Ca(IO3)2...Ca2+......IO3- 
<span>some.......0..........0 </span>
<span>less.......+x......+2x </span>
<span>less........x.........2x 
</span>
<span>Ca(IO₃)₂ ⇄ Ca⁺² + 2 IO⁻³
</span>
K sp = [Ca⁺²][IO₃⁻]²
K sp = (x) (2 x)² = 4 x³
7.1 x 10⁻⁷ = 4 x³
<span>x = molar solubility = 5.6 x 10</span>⁻³ M

The answer is 5.6 x 10 ^ 3 M. (molar solubility)
5 0
3 years ago
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Typically, alkali metals tend to have
vladimir2022 [97]

Answer:

d

Explanation:

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5 0
3 years ago
The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because?.
Daniel [21]

The phosphorylation of fructose 6-phosphate to fructose-1,6-bisphosphate is the committed step in glycolysis because. it is the rate-limiting step

<h3>What is phosphorylation?</h3>

The first step in the metabolism of carbohydrates is frequently their phosphorylation. Because the phosphate group stops the molecules from migrating back across the transporter, phosphorylation enables cells to store carbohydrates. Glucose phosphorylation is a crucial step in the metabolism of sugar. In the first phase of glycolysis, D-glucose is converted to D-glucose-6-phosphate using the chemical equation D-glucose + ATP D-glucose-6-phosphate + ADP G° = 16.7 kJ/mol (° signifies measurement under standard conditions).

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encouraging certain glucose transporters to translocate to the cell membrane.

To learn more about phosphorylation from the given link:

brainly.com/question/2138188

#SPJ4

7 0
1 year ago
An atom has a mass number of 24 and 13 neutrons. what is the atomic number of this atom? express your answer as an integer.
Murljashka [212]
A=24
N(n)=13

N(p)=A-N(n)

N(p)=24-13=11

²⁴Na - sodium

atomic number is 11
5 0
3 years ago
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