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Bad White [126]
3 years ago
15

In square meters, what is the area of a single face of a cube that has a volume of 125 cubic meters?

Mathematics
1 answer:
Oliga [24]3 years ago
5 0

Answer:

The answer is 5 meters

Step-by-step explanation:

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Round 409514.963259 to the nearest tenth.
olga_2 [115]

Answer:

Step-by-step explanation:

409515 Is the answer because you round up because the hundredths place number is greater than 5 so you round up, BUT you gotta roung 9 up but then you gotta add 1 to the ones place

6 0
3 years ago
Read 2 more answers
Triangle ABC is graphed below with vertices at A (-4,5), B (-6, -4) and C (4,-4). Use the following rule to produce
guapka [62]

Step-by-step explanation:

A(-4, 5) => A'(-4+2, -5) = A'(-2, -5)

B(-6, -4) => B'(-6+2, -(-4)) = B'(-4, 4)

C(4, -4) => C'(4+2, -(-4)) = C'(6, 4)

Hence the new coordinates are A'(-2, -5), B'(-4, 4) and C'(6, 4).

7 0
3 years ago
5/8 - (- 7/8) in simplest form
ANTONII [103]

Answer: 3/2

Step-by-step explanation:

12/8=3/2

6 0
2 years ago
To the nearest tenth, find the perimeter of ∆ABC with vertices A(-1,4), B(-2,1) and C(2,1). Show your work.
Sladkaya [172]
A=(-1,4)=(xa,ya)→xa=-1, ya=4
B=(-2,1)=(xb,yb)→xb=-2, yb=1
C=(2,1)=(xc,yc)→xc=2, yc=1

Perimeter <span>of ∆ABC: P=AB+BC+AC

AB=d A-B=sqrt [ (xb-xa)^2+(yb-ya)^2 ]
AB=sqrt [ (-2-(-1))^2+(1-4)^2]
AB=sqrt [ (-2+1)^2+(-3)^2]
AB=sqrt [ (-1)^2+9]
AB=sqrt [ 1+9]
AB=sqrt [10]
AB=3.162277660

</span>BC=d B-C=sqrt [ (xc-xb)^2+(yc-yb)^2 ]
BC=sqrt [ (2-(-2))^2+(1-1)^2]
BC=sqrt [ (2+2)^2+(0)^2]
BC=sqrt [ (4)^2+0]
BC=sqrt [ 16+0]
BC=sqrt [16]
BC=4

AC=d A-C=sqrt [ (xc-xa)^2+(yc-ya)^2 ]
AC=sqrt [ (2-(-1))^2+(1-4)^2]
AC=sqrt [ (2+1)^2+(-3)^2]
AC=sqrt [ (3)^2+9]
AC=sqrt [ 9+9]
AC=sqrt [9*2]
AC=sqrt [9] * sqrt [2]
AC=3 sqrt [2]
AC=3 (1.414213562)
AC=4.242640686

P=AB+BC+AC
P=3.162277660+4+4.242640686
P=11.40491834
To the nearest tenth:
P=11.4

Answer: <span>The perimeter of ∆ABC is 11.4 units</span>
7 0
2 years ago
Please help need answer ASAP
weqwewe [10]
Answered! Good luck!

6 0
2 years ago
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