When we use arcsine, we are finding the angle while giving the trigonometric ratio.
Arcsin(u) = theta can be rewritten as:
sin(theta) = u
Sine is opposite over hypotenuse, so u/1 means that the side opposite to theta (the y value) is u, and the hypotenuse is 1.
We can use Pythagorean Theorem to find the adjacent (x value).
1^2 - u^2 = x^2
x = sqrt(1-u^2)
Back to the original question, we are trying to find cos(arcsin(u)). We just solved all the sides for our triangle using arcsin(u). Now we need to do cos(u).
Cosine is adjacent over hypotenuse.
So our answer is sqrt(1-u^2)/1
Or just sqrt(1-u^2)
Answer: since it doesnt say 620 is included , we can conclude that x>620, not x>=620 so the 8th week would be cut just short, so answer is 7
aka
fewer than 8 weeks
Step-by-step explanation:
1200-620=580
580/72.50=8
Step-by-step explanation:
The outer angle at the top C of the ABC is 112 °. If the bisector of the side AB intersects the side AC at point Q and the segment BQ is perpendicular to AC, find the magnitude of ABC
This would be ( using the Pythagoras theorem) = sqrt (3^2 + 4^2) = sqrt 25
= 5 units (answer).
