What is the commutative, associative, and distributive property of 3a plus 5a plus 2b

2 answers:

5 0

Question: What is the commutative, associative, and distributive property of 3a plus 5a plus 2b0.

Answer:Defintion of Commutative property holds for both addition and multiplication. That is: the operations addition and multiplication are commutative over the set of real numbers. That means, for any two real numbers x and. y, x + y = y + x and xy = yx. Definiton of associative In mathematics, the associative property is a property of some binary operations. In propositional logic, associativity is a valid rule of replacement for expressions in logical proofs and distrive property means The Distributive Property is an algebra property which is used to multiply a single term and two or more terms inside a set of parentheses. I really hope this helped thx for the question!

VLD [36.1K]3 years ago

3 0

Commutative: a+b=b+a
associative: (a+b)+c=a+(b+c)
distributive: ab+ac=a(b+c)

so
3a+5a+2b
we can show distributive with the a terms
3a+5a=a(3+5)=8a
8a+2b
we can distribute again
2(4a)+2b=2(4a+b)

not sure how to show commutative or associative
I guess
3a+5a+2b=2b+3a+5a

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On a coordinate plane, 4 lines are shown. Line L M goes through (negative 5, negative 3) and (0, 3). Line N O goes through (nega

miv72 [106K]

Answer:

The slope of line LM is perpendicular to the given line.

Step-by-step explanation:

L (- 5, - 3), M (0, 3)

N (- 6, - 5) , O (0, 0)

J (- 6, 1) , K (0, - 4)

Slope of given line = -5/6

Slope of perpendicular line = 6/5

Slope of line LM

$\frac{3 + 3}{0 + 5}=\frac{6}{5}$

Slope of line NO

$\frac{0+5}{0+6}=\frac{5}{6}$

Slope of line JK

$\frac{-4-1}{0+6}=\frac{-5}{6}$

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yarga [219]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

What is the mathematical induction of <br> 1+3+5+...+(2n-1)=n^2

Lena [83]

Let $S(n)$ be the statement that

$1+3+5+\cdots+(2n-1)=\displaystyle\sum_{k=1}^n(2k-1)=n^2$

Check to see that $S(n)$ holds for $n=1$ :

$\displaystyle\sum_{k=1}^1(2k-1)=1=1^2\implies S(1)\text{ is true}$

Now suppose that $S(N)$ is true, and use that assumption to show that $S(N+1)$ must also be true. When $n=N+1$ , you have

$\displaystyle\sum_{k=1}^{N+1}(2k-1)=\sum_{k=1}^N(2k-1)+2(N+1)-1$
$=N^2+2(N+1)-1$
$=N^2+2N+1$
$=(N+1)^2$

and so $S(N+1)$ is also true, thus proving the statement is true for all $n$ .