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sergiy2304 [10]
3 years ago
5

If the radius and diameter is 2 decimeter then its diameter is in centimetre​

Mathematics
1 answer:
Soloha48 [4]3 years ago
8 0

Answer:

Sorry but I dont thin that the radius AND the diameter can be 2 since the radius is half the diameter

Step-by-step explanation:

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A circular fountain has a radius of 9.4 feet find its diameter and circumference to the nearest tenth
ad-work [718]

Answer:

18.8 feet, 59.1 feet to the nearest tenth

Step-by-step explanation:

The diameter is the line drawn that divides the circle into two while the circumference is the perimeter of the circle. Both are a measure of the radius of the circle.

The diameter D = 2r where r is the radius of the circle

The circumference = 2Πr = ΠD where Π = 22/7

Given that the circular fountain has a radius of 9.4 feet

Its diameter =  2 × 9.4 feet = 18.8 feet

The circumference = 22/7 × 18.8 feet

=59.09 feet

≈ 59.1 feet to the nearest tenth

7 0
3 years ago
Read 2 more answers
Which ordered pair is a solution for the system of equations? {3x−5y=152x−y=−4 (−5, −6) (0, 3) (2, 8) (−6, −11)
SashulF [63]
3x-5y =15

2x-y=-4 
multiply the equation by 5 and then subtract   equation 2 from equation 1
so 3x-5y =15
    10x-5y =-20
-7x =35 x =-5  
plug in the value of x in the second equation -10 -y =-4  - y= -4 +10 y =-6
x=-5 y=-6



7 0
4 years ago
Read 2 more answers
Find the length of B to the nearest tenth using the Pythagorean theorem.​
bekas [8.4K]

Step-by-step explanation:

Here

BC=P=10

AC=B=b

AB=H=15

then using fourmula

h^2= p^2+ b^2

b^2= 15×15 - 10× 10

b^2= 125

b=11.2

4 0
3 years ago
A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando
Allushta [10]

<u>Answer:</u>

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744  

<u>Solution:</u>

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) \times p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = \frac{\text { number of good coils }}{\text { total number of coils }}

Hence, p(getting 2 good coil for two selection) = \frac{88}{100} \times \frac{88}{100} =\bold{0.7744}

5 0
3 years ago
PLZ HELP I TRIED LIKE 20 TIMES AND GOT IT WRONG
Tju [1.3M]

Answer:

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3 years ago
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