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pochemuha
2 years ago
10

(b)What is the probability of choosing the letter A at random from the word ALPHABET?

Mathematics
1 answer:
lakkis [162]2 years ago
8 0

Answer:

3b: 1/26

4i: 1/4

4ii: 1/13

4iii 1/13

4iv: 1/13

4v: 3/13

Step-by-step explanation:

3b. there are 26 letters in the alphabet, and there is only 1 S, thus the answer is 1/26

4i: There are 13 cards in each suite, so there is a 13/52 = 1/4 chance.

4ii: There are four aces (Spades, Hearts, Diamonds, and Clubs) so thus the answer is 4/52 = 1/13

4iii: there are four 7's (Spades, Hearts, Diamonds, and Clubs) so thus the answer is 4/52 = 1/13

4iv: there is a king in each of the suites, therefore the answer is 4/52 = 1/13

4v: there are a total of 12 court cards (4 kings, 4 queens, and 4 jacks) thus the answer is 12/52 = 3/13

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ANSWER

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EXPLANATION

The problem represents a geometric progression.

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a_n=ar^{n\text{ - 1}}

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The first term from the table is the first price (for the first month). That is $80.00

To find the common ratio, we divide a term by its preceeding term.

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We have:

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\begin{gathered} a_8\text{ = 80 }\cdot0.9^{(8\text{ - 1)}} \\ a_8\text{ = 80 }\cdot0.9^7 \\ a_8\text{ = \$38.26} \end{gathered}

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9 months ago
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brainly.com/question/2375289

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