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3 years ago

A company has 200 machines. Each machine has 12% probability of not working.

Mathematics

1 answer:

Eduardwww [97]3 years ago

4 0

1) This probability is given by

... C(40,5)·0.12⁵·0.88³⁵ ≈ 0.18665 . . . . . where C(n, k) = n!/(k!(n-k)!)

2) This probability is given by

... 0.88⁴⁰ ≈ 0.00602

3) This is the complement of the probability that all have failed.

... 1 - 0.12⁴⁰ ≈ 1.0000

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The circumference of a circle is 60 pi cm. What is the length of an arc of 140 degrees

son4ous [18]

<span>circumference = 60*PI cm
If an arc is 140 degrees of the circle then its length =
</span>
<span>60*PI cm * (140 / 360)
arc length = 23.33333 cm

</span>

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2 years ago

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The length of the rectangle is 5 inches more than the width. The perimeter of the rectangle is 42 inches. Write an equation to m

Sunny_sXe [5.5K]

Answer:

<h2>Length = 13 in. </h2>

Step-by-step explanation:

perimeter of a rectangle (P) = 2L + 2W

where;

P = 42 in.

Length (L) = 5 + W

Find:

length (L) of the rectangle

solution:

P = 2L + 2W

42 = 2(5 + W) + 2W

42 = 10 + 2W + 2W

42 - 10 = 4W

32 = 4W

W = 32/4

W = 8

Length (L) = 5 + W

= 5 + 8

= 13 in

proof:

42 = 2(13) + 2(8)

42 = 42 in

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3 years ago

Identify the scale factor

nydimaria [60]

Answer:

Step-by-step explanation:

k = 4/24 = 1/6

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3 years ago

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When playing the roulette at a casino, you have exactly 1/35 chance of winning in each round if you play a single number. Your f

Vikentia [17]

Answer:

0.2275 = 22.75% probability that you actually won that round

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Fireworks going off

Event B: You won

Probability of fireworks going off.

100% of 1/35 = 0.0286(when you win)

10% of 34/35 = 0.9714(you lost). So

$P(A) = 0.0286 + 0.1*0.9714 = 0.12574$

Probability of you winning and fireworks going off:

100% of 1/35, so $P(A \cap B) = 0.0286$

If you failed to see the outcome of a round, but you see the fireworks going off, then what is the probability that you actually won that round?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0286}{0.12574} = 0.2275$

0.2275 = 22.75% probability that you actually won that round

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3 years ago

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Answer:

3.50 divided by 5=70 70 times five is 3.50

Step-by-step explanation:

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