Answer:
<em>The man paid $200 for the cow</em>
Step-by-step explanation:
<u>System of Equations</u>
Let's call:
x = price of the cow
y = price of the horse
The man bought the cow and the horse for $500, thus
x + y = 500 [1]
The cow was sold at a profit of 10%, thus:
Sale price of the cow= 1.1x
The horse was sold at a loss of 10%, thus:
Sale price of the horse= 0.9y
The total operation was a 2% loss, i.e. 0.98*500=490. Thus, we have:
1.1x + 0.9y = 490 [2]
From [1]:
y = 500 - x
Substituting in [2]:
1.1x + 0.9(500 - x) = 490
Operating:
1.1x + 450 - 0.9x = 490
0.2x = 490 - 450 = 40
x = 40/0.2
x = 200
The man paid $200 for the cow
Answer:
4+4+1
Step-by-step explanation:
Answer:
ku hgkjfghdehfv bfd
Step-by-step explanation:
