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JulijaS [17]
3 years ago
14

The area of a blackboard is

Mathematics
2 answers:
noname [10]3 years ago
8 0

Answer:

3/2

Step-by-step explanation:

unit rate  describes how many units of the first type of quantity corresponds to one unit of the second type of quantity so:

1.1/3= 3.1+1÷3=4/3

8/9÷4/3=3/2

Sonja [21]3 years ago
7 0

Answer:

<h2>There are 6 square yards of blackboard per 2 square yards per poster.</h2>

Step-by-step explanation:

The unit rate refers to how many area units of the poster are in the blackboard.

To find this rate, we just have to divide the area of the blackboard by the area of the poster.

B=1\frac{1}{3}=\frac{4}{3}

Where B represents the area of the blackboard in square yards.

P=\frac{8}{9}

Where P represents the area of the poster.

Now, the ratio is

r= \frac{B}{P}=\frac{4}{3} \div \frac{8}{9}=\frac{4}{3} \times \frac{9}{8}=\frac{36}{24}\\r=\frac{6}{4}=\frac{3}{2}=1.5

This mean that the unit rate is 1.5, that is, there are 6 square yards of blackboard per 2 square yards per poster.

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Answer:

thats all i know

Step-by-step explanation:

1.5+8

2.3×4

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2 years ago
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Which ratio is higher 15:20 or 12:16. for 35 points
Margarita [4]

To find which ratio is higher, we can first convert the ratios into fractions (that makes it easier, at least for me) and then simplify the fractions and see which one is greater.

Since ratios are basically division, 15:20 = \frac{15}{20}, and

12:16 = \frac{12}{16}

Now we simplify these fractions. 15 and 20 have a GCF of 5, so taking out the common number gives us the simplified fraction of \frac{3}{4}.

12 and 16 have a GCF of 4, so taking out the common number gives us the simplified fraction of \frac{3}{4}. Since \frac{3}{4} = \frac{3}{4}, these ratios are the same.

8 0
4 years ago
ABCDE ~ FGHIJ. Figure 2 is a dilation of figure 1, and the scale factor is 0.6. Given that FG = 12 cm, find AB.
avanturin [10]
We known that the figures are similar if and only if the corresponding sides and and angles have the common scale factor. In this item, the scale factor is 0.6. The length of AB is determined by multiplying the length of FG with the scale factor. That is,
                            AB = FG x scale factor
                            AB = (12 cm) x 0.6
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Thus, the length of side AB is 7.2 cm. 
6 0
3 years ago
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In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.
Tema [17]

Answer:

Area  \approx 1149\ cm^2

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to \angle W)

Side u = 83 cm (It is the side opposite to \angle U)

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

A = \dfrac{1}{2}\times a\times b\times sinC

Where a and b are the two sides and

\angle C is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A  \approx 1149\ cm^2

So, the <em>area </em>of given triangle to the nearest square centimetre is:

Area  \approx 1149\ cm^2

8 0
4 years ago
Two perpendicular lines intersect at the origin. If the slope of the first line is .5, what is the equation of the second line?.
Sedaia [141]
The origin is at the point (0,0). Therefore, the y-intercept will be 0. For two points to be perpendicular, the slopes must be opposite reciprocals of each other. .5 can be seen as 1/2, so the reciprocal is 2, and it is positive, making that 2 negative. Your equation would be y = -2x. 
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3 years ago
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