X ml - <span>25% alcohol mixture
y ml - </span><span>90% alcohol mixture

x+y = 455

0.25x ml alcohol in </span>x ml of 25% alcohol mixture
0.9y ml alcohol in y ml of  90% alcohol mixture
0.75*455= 341.25 ml alcohol in 455 ml of  75% alcohol mixture

0.25x+0.9y=341.25

System of equations:

x+y = 455 /*(-0.25) ------> -0.25x-0.25y = -0.25*455
0.25x+0.9y=341.25

-0.25x-0.25y=-113.75
0.25x+0.9y=341.25 Add both equations

0.25x+0.9y-0.25x-0.25y=341.25-113.75
0.65y =227.5
y=227.5/0.65 = 350 ml  of  90% alcohol mixture

x+y=455
x+355=455
x=100 ml of  25% alcohol mixture

8 0

3 years ago

Consider 5.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.30 L and the temperature is increased to 4

lakkis [162]

Answer:

P₂ = 1.12 atm

Explanation:

To find the new pressure, you need to use the Combined Gas Law:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

In this equation, "P₁", "V₁", and "T₁" represent the initial pressure, volume, and temperature. "P₂", "V₂", and "T₂" represent the new pressure, volume, and temperature. Before plugging the values into the equation, you need to

(1) convert the pressure from mmHg to atm (760 mmHg = 1 atm)

(2) convert the temperatures from Celsius to Kelvin (°C + 273)

The final answer should have 3 sig figs like the given values.

P₁ = 365 mmHg / 760 = 0.480 atm P₂ = ? atm

V₁ = 5.00 L V₂ = 2.30 L

T₁ = 20°C + 273 = 293 K T₂ = 40°C + 273 = 313 K

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$ <----- Combined Gas Law

$\frac{(0.480 atm)(5.00 L)}{293 K}=\frac{P_2(2.30 L)}{313 K}$ <----- Insert values

$0.00819=\frac{P_2(2.30 L)}{313 K}$ <----- Simplify left side

$2.56 = P_2(2.30L)$ <----- Multiply both sides by 313

$1.12 = P_2$ <----- Divide both sides by 2.30

6 0

11 months ago

Identify whather the following are elements, compounds and mixture.

astra-53 [7]

1 is element 2 is element 3 is compound 4 is element 5 is nothing in and water is a compound

6 0

3 years ago

Which statement best describes what is taking place in this half reaction? Iron is being reduced. Iron is being oxidized. Iron i

Mashutka [201]

If the reaction is a corrosion reaction, then the Iron would be losing electrons. The answer is:
Iron is being oxidized.
Consequently, since the Iron causes the gaining of electrons of another species or substance, it is considered as the reducing agent.

4 0

3 years ago