First let's convert the minutes to hours (multiply minutes by 60 to get hours):
30 × 60 = 1,800 drops/hour
Now that you know how much drops there are per hour, you can multiply this answer by 3 to work out how many drops there are in 3 hours:
1,800 × 3 = 5,400 drops
We know that 5 drops is equal to 1 ml, so we can divide 5,400 by 5 to work out the amount of ml:
5,400 ÷ 5 = 1,080 ml
Therefore, your final answer is 1,080 millilitres (ml)
Answer:
The mass of the precipitate that AgCl is 3.5803 g.
Explanation:
a) To calculate the molarity of solution, we use the equation:

We are given:
Mass of solute (NaCl) = 1.46 g
Molar mass of sulfuric acid = 58.5 g/mol
Volume of solution = 

Putting values in above equation, we get:

0.09982 M is the concentration of the sodium chloride solution.
b) 
Moles of NaCl = 
according to reaction 1 mol of NaCl gives 1 mol of AgCl.
Then 0.02495 moles of NaCl will give:
of AgCl
Mass of 0.02495 moles of AgCl:

The mass of the precipitate that AgCl is 3.5803 g.
Yes it is used , hope this helps
We can predict formula of ionic compounds by:
- Take a look at where the elements are listed on the periodic table.
- The amount of electrons that an element would need to gain or lose in order to resemble an atom of a nearby noble gas is one of the similarities that atoms in the same column as one another (group) tend to display.
- Alkali metal group I ions have +1 charges.
- Alkaline earth metals (group 2 ions) have a +2 charge.
- Nonmetal group 6 ions have a charge of -2.
- Halides in group 7 have a -1 charge.
- The charges of the transition metals cannot be predicted in a straightforward manner.
- Check out a table of charges (valences) to see potential values. The +1, +2, and +3 charges are most frequently employed in beginning and general chemistry courses.
- Keep in mind that the positive ion is always stated first when writing an ionic compound's formula.
These are the few guidelines we can use to product formula.
Learn more about ionic compounds here:
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Answer: it is soluble
Explanation: nitrates are soluble.