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3 years ago

Why sodium is active element...

2 answers:

8 0

The other answer here is correct, but if you’re looking from a more structural view then here is it:
Sodium has only one electron it it’s outermost orbital, and because of this it has a really high tendency In giving up that electron in order to get into a more stable electron configuration.

lapo4ka [179]3 years ago

7 0

Answer:

here is your answer

Explanation:

1. sodium sodium is very reactive metal

2. when it exposed in air it automatically form Na2O.

3. when when it put in water it reacts visoroustly and start burning on water.

( due to this it is called active element)

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3 years ago

Calculate the mass of a solute in a 10% salt solution if the mass is 350 grams.

Lyrx [107]

Answer: The mass of a solute is 35 grams

Explanation:

To calculate the mass percentage of solute, we use the equation:

$\text{Mass percent of solute}=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100$

Mass percent of solute = 10 %

Mass of solution = 350 g

Putting values in above equation, we get:

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3 years ago

Liquid octane CH3CH26CH3 reacts with gaseous oxygen gas O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O. If 2.80g

oee [108]

Answer:

54%

Explanation:

The balanced equation is:

$2 CH_{3}(CH_{2})_{6}CH_{3} + 25 O_{2} = 16 CO_{2} + 18 H_{2}O$

The first step is to determine the limiting reactant. For this, we calculate the moles of each given component and divide the result for the stoichiometric coefficient.

3.4 g octane / 114.23 g/mol = 0.030 mol octane

0.030 mol octane/2=0.015

5.9 g O2 / 32 g/mol = 0.18 mol O2

0.18 mol O2/25= 0.0074 mol

The lower number, in this case oxygen, is the limiting reactant. The value corresponds to the theoretical yield of the reaction.

Similarly, the real yield is calculated from the product.

2.80 g CO2/ 44.01 g/mol = 0.0636 mol CO2

0.0636 mol CO2/16 = 0.00398 mol

The percent yield is the ratio of the 2 multiplied by a hundred, then

Percent yield= 0.0398/0.0074 *100 = 54%

3 0

3 years ago

Why sodium is active element...​

Why sodium is active element...