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ratelena [41]
3 years ago
8

Why sodium is active element...​

Chemistry
2 answers:
OleMash [197]3 years ago
8 0
The other answer here is correct, but if you’re looking from a more structural view then here is it:
Sodium has only one electron it it’s outermost orbital, and because of this it has a really high tendency In giving up that electron in order to get into a more stable electron configuration.
lapo4ka [179]3 years ago
7 0

Answer:

here is your answer

Explanation:

1. sodium sodium is very reactive metal

2. when it exposed in air it automatically form Na2O.

3. when when it put in water it reacts visoroustly and start burning on water.

( due to this it is called active element)

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A sample of a compound contains 41.33 g of carbon and 8.67 g of hydrogen. The molar mass of the
mihalych1998 [28]

Answer:

C6H15

Explanation:

First, we calculate the empirical formula as follows:

C = 41.33 g

H = 8.67 g

We convert each mass value to mole by dividing each element by its molar mass (C = 12g/mol, H = 1g/mol)

C = 41.33g ÷ 12g/mol = 3.44mol

H = 8.67g ÷ 1g/mol = 8.67mol

Next, we divide each mole value by the smallest (3.44mol)

C = 3.44mol ÷ 3.44mol = 1

H = 8.67mol ÷ 3.44mol = 2.52

We multiply this ratio by 2 to get a simple whole number ratio

C = 1 × 2 = 2

H = 2.52 × 2 = 5.04

Based on this, the whole number ratio of C and H is 2:5, hence, the empirical formula is C2H5.

The molecular mass of the compound is given as 87.18 g/mol, hence, the molecular formula is calculated as follows:

(C2H5)n = 87.18

[12(2) + 1(5)]n = 87.18

[24 + 5]n = 87.18

(29)n = 87.18

n = 87.18 ÷ 29

n = 3.006

Approximately to whole number, n = 3

Hence, the molecular formula of the compound is [C2H5]3

= C6H15

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How many moles are there in 87.2 g of zinc fluoride?
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