Question

Subtract the sum of 5/9 and -2/9 from the sum of 7/12 and -5/12​

Answer 1

$[\frac{7}{12} + ( - \frac{5}{12} )] -[ \frac{5}{9} + ( - \frac{2}{9} )] \\ \\ = [ \frac{7}{12} - \frac{5}{12} ] - [ \frac{5}{9} - \frac{2}{9} ] \\ \\ = [ \frac{7 - 5}{12} ] - [ \frac{5 - 2}{9} ] \\ \\ = \frac{2}{12} - \frac{3}{9} \\ \\ = \cancel \frac{2}{12} - \cancel \frac{3}{9} \\ \\ = \frac{1}{6} - \frac{1}{3} \\ \\ = \frac{1 - 2}{6} \\ \\ = - \frac{1}{6}$

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Answer 2

Answer:

         $\frac{-1}{6}$

Step-by-step explanation:

$Sum \ of \ \ \frac{5}{9} \ and \ \frac{-2}{9} =\frac{5}{9} + \frac{-2}{9} = \frac{5-2}{9} = \frac {3}{9} = \frac{1}{3}$

$Sum \ of \ \frac{7}{12} \ and \ \frac{-5}{12} = \frac{7}{12} \ + \ \frac{-5}{12} = \frac{7-5}{12} = \frac{2}{12} = \frac{1}{6}$

$subtract \ first \ from \ second = \frac{1}{6} - \frac{1}{3} = \frac{1 -2}{6} = \frac{-1}{6}$