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2 years ago

Hey, I have some algebra questions, I need to complete for tomorrow. One of them is: Simplify 4a + 12a.

Mathematics

1 answer:

Nimfa-mama [501]2 years ago

3 0

Answer:

16a

Step-by-step explanation:

4a+12a=16a since they are the same variables.

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Help is really needed...

ANTONII [103]

Answer:

240m^3

Step-by-step explanation:

Volume = length x width x height.

5x12x4= 240

6 0

2 years ago

PLS HELP WILL MARK AS BRAINLIEST

soldier1979 [14.2K]

Answer:

26. the y intercept is -6

27. the y intercept is 2

28. the y intercept is -3

29. I cant answer because it is cut off in the picture...

Step-by-step explanation:

These equations follow a simple formula- the slope formula

y=mx+b

In this formula:

b is the y intercept

m is the slope that is multiplied by x

hope this helps:)

please crown me brainliest!!!

3 0

1 year ago

Can you help me with these questions???

lord [1]

3. 28 Quarters and 5 dimes.

3 0

2 years ago

Serena estimates that she can paint 60 square feet of wall space every half-hour. Write an equation for the relationship with ti

Katarina [22]

Answer:

So, the relationship with i hours as the indecent variables would be

Serena can't paint 400 square feet of wall space of wall space in 3.5 hours.

Step-by-step explanation:

Since we have given that

Area that she can paint = 60 square feet

Time taken = half hour = 30 minutes = 0.5 hours

Using "Unitary method, we get that

In 0.5 hours, she can paint = 60 square feet

In 1 hour, she can paint =

In i hours, she can paint =

Let the total area she can paint be 'y'.

So, the relationship with i hours as the indecent variables would be

Now, Can Serena paint 400 square feet of wall space i. 3.5 hours

We put y = 400 and i = 3.5 hours to check whether it is equal or not.

Hence, Serena can't paint 400 square feet of wall space of wall space in 3.5 hours.

6 0

2 years ago

Read 2 more answers

Solve y ' ' + 4 y = 0 , y ( 0 ) = 2 , y ' ( 0 ) = 2 The resulting oscillation will have Amplitude: Period: If your solution is A

Vlad [161]

Answer:

$y(x)=sin(2x)+2cos(2x)$

Step-by-step explanation:

$y''+4y=0$

This is a homogeneous linear equation. So, assume a solution will be proportional to:

$e^{\lambda x} \\\\for\hspace{3}some\hspace{3}constant\hspace{3}\lambda$

Now, substitute $y(x)=e^{\lambda x}$ into the differential equation:

$\frac{d^2}{dx^2} (e^{\lambda x} ) +4e^{\lambda x} =0$

Using the characteristic equation:

$\lambda ^2 e^{\lambda x} + 4e^{\lambda x} =0$

Factor out $e^{\lambda x}$

$e^{\lambda x}(\lambda ^2 +4) =0$

Where:

$e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda$

Therefore the zeros must come from the polynomial:

$\lambda^2+4 =0$

Solving for $\lambda$ :

$\lambda =\pm2i$

These roots give the next solutions:

$y_1(x)=c_1 e^{2ix} \\\\and\\\\y_2(x)=c_2 e^{-2ix}$

Where $c_1$ and $c_2$ are arbitrary constants. Now, the general solution is the sum of the previous solutions:

$y(x)=c_1 e^{2ix} +c_2 e^{-2ix}$

Using Euler's identity:

$e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)$

$y(x)=c_1 (cos(2x)+isin(2x))+c_2(cos(2x)-isin(2x))\\\\Regroup\\\\y(x)=(c_1+c_2)cos(2x) +i(c_1-c_2)sin(2x)\\$

Redefine:

$i(c_1-c_2)=c_1\\\\c_1+c_2=c_2$

Since these are arbitrary constants

$y(x)=c_1sin(2x)+c_2cos(2x)$

Now, let's find its derivative in order to find $c_1$ and $c_2$

$y'(x)=2c_1 cos(2x)-2c_2sin(2x)$

Evaluating $y(0)=2$ :

$y(0)=2=c_1sin(0)+c_2cos(0)\\\\2=c_2$

Evaluating $y'(0)=2$ :

$y'(0)=2=2c_1cos(0)-2c_2sin(0)\\\\2=2c_1\\\\c_1=1$

Finally, the solution is given by:

$y(x)=sin(2x)+2cos(2x)$

5 0

3 years ago

Hey, I have some algebra questions, I need to complete for tomorrow. One of them is: Simplify 4a + 12a. ​

Hey, I have some algebra questions, I need to complete for tomorrow. One of them is: Simplify 4a + 12a.