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mixer [17]
3 years ago
11

F(–7) if f(x) = 3x + 6

Mathematics
1 answer:
drek231 [11]3 years ago
5 0

Step-by-step explanation:

f(–7) if f(x) = 3x + 6

3(-7) +6

-21+6

x= - 15

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\bf \begin{array}{lllll}
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\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-1)=0(x-2)
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7 0
3 years ago
A ball is dropped straight down from a height of 200 feet. After 1 second? The hall is 184 feet above the ground. After 2 second
mote1985 [20]

The motion of the ball dropped from height is a free fall motion due to

gravitational acceleration.

<h3>Correct response;</h3>
  • The equation that models the height is; <u>y = -16·x²</u>

<h3>Method for arriving at the above equation;</h3><h3>Given values;</h3>

\begin{tabular}{|c|c|}Height (feet)&Time (s)\\200&0\\184&1\\136&2\end{array}\right]

<h3>Required:</h3>

To select the equation that models the height, <em>y</em>, of the ball <em>x</em> seconds after

its dropped;

<h3>Solution:</h3>

From the above table, we have that the first difference is not a constant

The second difference is = 48 - 16 = 32

Taking the second difference as a constant, we have the following

quadratic sequence;

y = a·x²  + b·x + c

Where;

x = The time in seconds

y = The height after <em>x</em> seconds

  • At x = 0, we have;

200 = a·0² + b × 0 + c

Therefore;

c = 0

  • At<em> x</em> = 1, we have;

184 = a × 1² + b × 1 + 200

184 = a + b + 200

a + b = -16

a = -16 - b

  • At <em>x</em> = 2, we have;

136 = a × 2² + b × 2 + 200

136 = 4·a + 2·b + 200

-64 = 4·a + 2×b

Therefore;

-64 = 4 × (-16 - b) + 2×b

-64 = -64 - 4·b + 2×b

b = 0

a + b = -16

Therefore;

a + 0 = -16

a = -16

The equation that models the height is; y = <u>-16·x²</u>

Learn more about quadratic function here;

brainly.com/question/2293136

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