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nikitadnepr [17]
3 years ago
6

U = 6i – 10j g= -81 – 11j Find: -3u + 5g

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0

Answer:

-3u + 5g =-58i -25j

Step-by-step explanation:

Given

u = 6i - 10j

g=-8i - 11j

Required

-3u + 5g

We have:

-3u + 5g

This gives:

-3u + 5g = -3(6i - 10j) + 5(-8i - 11j)

Open bracket

-3u + 5g = -18i + 30j - 40i - 55j

Collect like terms

-3u + 5g = -18i - 40i+ 30j  - 55j

-3u + 5g =-58i -25j

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Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?
Artemon [7]

Answer:

The equation y=\frac{-x^2-6x+31}{8} represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }, we find that the distance between (x, y) is

\sqrt{(x+3)^2+(y-3)^2}

and the distance between (x, y) and the directrix y = 7 is

\sqrt{(y-7)^2}.

On the parabola, these distances are equal so, we solve for y:

\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}

6 0
3 years ago
Original price $125 discount ? sale price $81.25
levacccp [35]

Answer:(125-81.25)/125 = 0.35 = 35%

Step-by-step explanation:

7 0
3 years ago
Which is the graph of 5 log (x + 3) = 5?
algol13
????????????????????
5 0
4 years ago
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Choose all the fractions that are equivalent to1/7. (Click all that apply.)
Alchen [17]

Answer:

2/14, 4/28, 5/35, 7/70 or just 2/14

Step-by-step explanation:

Multiply both the numerator and denominator of 1/7 by 2, to get 2/14, or 2:14

And multiply the numerator and denominator of 1/7 by 3, to get 3/21, or 3:21. So 2:14 and 3:21 are two ratios that are equal to 1:7.

8 0
3 years ago
The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c =
avanturin [10]
Given:

The function, f(x) = -2x^2 + x + 5

Quadratic equation: 0 = -2x^2 + x +5
where a = -2
            b = 1
            c = 5

The discriminate b^2 - 4ac = 41

To solve for the zeros of the quadratic function, use this formula:

x = ( -b +-√ (b^2 - 4ac) ) / 2a

x = ( 1 + √41 ) / 4  or 1.85
x = ( 1 - √41 ) / 4  or -1.35

Therefore, the zeros of the quadratic equation are 1.85 and -1.35. 
4 0
3 years ago
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