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Zarrin [17]
3 years ago
7

Can someone please help with this I am confused about how to know which side is a and c

Mathematics
1 answer:
KonstantinChe [14]3 years ago
7 0

Answer:

b=4

Step-by-step explanation:

The side opposite the right angle is the hypotenuse.  The sides touching the right angle are the legs

Since this is right triangle we can use the Pythagorean theorem

a^2+b^2 = c^2  where a and b are the legs and c is the hypotenuse

3^2+b^2 = 5^2

9+b^2 = 25

Subtract 9 from each side

9-9+b^2 = 25-9

b^2 =16

Take the square root of each side

sqrt(b^2) = sqrt(16)

b=4

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Given:

A table of values of a linear function.

To find:

The slope, y-intercept and equation of the function.

Solution:

Take any two points on the table.

Let the points are (-1, -3) and (0, -6).

Slope of the line:

$m=\frac{y_2-y_1}{x_2-x_1}

$m=\frac{-6-(-3)}{0-(-1)}

$m=\frac{-6+3}{0+1}

$m=\frac{-3}{1}

m = -3

Slope of the function = -3

y-intercept of the function is the point where x = 0.

In the table y = -6 when x = 0

y-intercept = -6

Equation of a line:

y = mx + c

where m is the slope and c is the y-intercept

y = -3x + (-6)

y = -3x - 6

Equation of a function is y = -3x - 6.

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How much would be earned on a $425 deposit earning 3% simple interest for 2 years? A. $12.75 B. $25.50 C. $25.88 D. $38.25
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Step-by-step explanation:

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2 years ago
The polynomial 6x2 + 37x – 60 represents an integer. Which expressions represent integer factors of 6x2 + 37x – 60 for all value
Temka [501]
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Step-by-step explanation:

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3 years ago
The given line passes through the points and (-4, -3) and (4, 1).
Debora [2.8K]

Answer:

The equation of the line is y - 3 = -2(x + 4)

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line which passes through the points (x1 , y1) and

  (x2 , y2) is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The product of the slopes of the perpendicular lines = -1

- That means if the slope of a line is m then the slope of the

  perpendicular line to this line is -1/m

- The point-slope of the equation is y - y_{1}=m(x - x_{1})

* lets solve the problem

∵ A given line passes through points (-4 , -3) and (4 , 1)

∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1

∴ The slope of the line m=\frac{1-(-3)}{4-(-4)}=\frac{1+3}{4+4}=\frac{4}{8}=\frac{1}{2}

- The slope of the line perpendicular to this line is -1/m

∵ m = 1/2

∴ The slope of the perpendicular line is -2

- Lets find the equation of the line whose slope is -2 and passes

 through point (-4 , 3)

∵ x1 = -4 , y1 = 3

∵ m = -2

∵ y - y1 = m(x - x1)

∴ y - 3 = -2(x - (-4))

∴ y - 3 = -2(x + 4)

* The equation of the line is y - 3 = -2(x + 4)

4 0
3 years ago
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