Given:
A table of values of a linear function.
To find:
The slope, y-intercept and equation of the function.
Solution:
Take any two points on the table.
Let the points are (-1, -3) and (0, -6).
Slope of the line:
m = -3
Slope of the function = -3
y-intercept of the function is the point where x = 0.
In the table y = -6 when x = 0
y-intercept = -6
Equation of a line:
y = mx + c
where m is the slope and c is the y-intercept
y = -3x + (-6)
y = -3x - 6
Equation of a function is y = -3x - 6.
Answer:
The equation of the line is y - 3 = -2(x + 4)
Step-by-step explanation:
* Lets explain how to solve the problem
- The slope of the line which passes through the points (x1 , y1) and
(x2 , y2) is
- The product of the slopes of the perpendicular lines = -1
- That means if the slope of a line is m then the slope of the
perpendicular line to this line is -1/m
- The point-slope of the equation is
* lets solve the problem
∵ A given line passes through points (-4 , -3) and (4 , 1)
∴ x1 = -4 , x2 = 4 and y1 = -3 , y2 = 1
∴ The slope of the line
- The slope of the line perpendicular to this line is -1/m
∵ m = 1/2
∴ The slope of the perpendicular line is -2
- Lets find the equation of the line whose slope is -2 and passes
through point (-4 , 3)
∵ x1 = -4 , y1 = 3
∵ m = -2
∵ y - y1 = m(x - x1)
∴ y - 3 = -2(x - (-4))
∴ y - 3 = -2(x + 4)
* The equation of the line is y - 3 = -2(x + 4)