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guajiro [1.7K]
3 years ago
5

Ravi bought 3 pens and 4 notebooks for $28. Lola bought 4 pens and 8

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
5 0

Answer:

5.50 Each

Step-by-step explanation:

grigory [225]3 years ago
3 0

Answer:

Step-by-step explanation:

3P + 4N = 28

6P+ 8N = 56

4P +8N  52

2P     = 4

P = 4/2 = 2  = $2

3(2)+4N = 28

4N = 28-6=22

N = 22/4 = 5.5= $5.50= cost of one notebook

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3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Can someone please please help me I don’t understand
Snowcat [4.5K]

Answer: Pretty sure the answer is C

Step-by-step explanation:

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3 years ago
Suppose h(t) = -4t^2+ 11t + 3 is the height of a diver above the water (in
Bingel [31]
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2 years ago
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What is the square root of x to the 10 power
Harrizon [31]

Answer:

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Step-by-step explanation:

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