Answer:
21
Step-by-step explanation:
factors of 42: 1,42, 2,<u>21</u>, 3,14, 6,7
factors of 63: 1,63, 3,<u>21</u>, 7,9
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So




The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
The art sculpture was 70 inches aka 5.9feet tall and if we round it well it would be 6feet so that would be its highest piont
Answer:
12 1/4
Step-by-step explanation:
common denominator between 8 and 2 is 4, adding those up will be 12.25 in decimal form or 12 1/4