Her studies
indicate that there is an inverse relationship between TV time and GPA, and
that a student who watched 15 hours of TV per week can be expected to have a
GPA of 3.5
In equation form
15 = k(1/3.5)
Solve for k
K = 15 * 3.5
<span>K = 52.5 is the constant
of variation</span>
Answer:
50, percentage decreased by 60% (percent) of its value = 20
Step-by-step explanation:
Answer:
TRUE
Step-by-step explanation:
Lateral area of cone is given by: πrl
where r is the radius and l is the slant height
Here r=r and l=2h
Hence, lateral area of cone A= π×r×2h
= 2πrh
Lateral area of cylinder is given by: 2πrh
where r is the radius and h is the height
Lateral area of cylinder B=2πrh
Clearly, both the lateral areas are equal
Hence, the statement that:The lateral surface area of cone A is equal to the lateral surface area of cylinder B. is:
True
The answer is C. 5.000039x10^6.
In order to change something into scientific notation you have to move the decimal place enough times to get the first number to be between 1 and 9. After that, you must count how many space you moved it and that is your exponent. Moving the decimal space to the left gives you a positive exponent. Moving it to the right gives you a negative exponent.
Answer:
El área del círculo que se encuentra en el cuadrado es de 78.5cm²
Step-by-step explanation:
Para resolver este ejercicio tenemos que pensar que un cuadrado tiene sus 4 lados iguales, por lo que todos sus lados medirán 10cm.
Ahora nos fijamos que necesitamos saber para calcular el área de un circulo
a = área
r = radio
π = 3.14
a = π * r²
como podemos ver no sabemos el valor del radio
como el circulo toca con los 4 lados del cuadrado sabemos que su radio sera la distancia del centro del cuadrado a cualquiera de los lados.
Entonces tenemos que dividir un lado por 2
10cm/2 = 5cm
El radio del circulo sera 5cm
Ahora que tenemos todos los datos podemos calcular el valor del área
a = 3.14 * (5cm)²
a = 3.14 * 25cm²
a = 78.5cm²
El área del círculo que se encuentra en el cuadrado es de 78.5cm²