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sesenic [268]
2 years ago
10

What is the average rate of change for the sequence shown below? (1 point)

Mathematics
1 answer:
Novosadov [1.4K]2 years ago
3 0

Answer:

I believe your answer is required in Rise/Run form.

Rise is -1 and Run is +2

so

-1/2

Step-by-step explanation:

Hope I helped You

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DON'T ANSWER FREE POINTSSSS
steposvetlana [31]

Answer:

\boxed{n = -13 - 4i}

Step-by-step explanation:

\text{Assuming } i=\sqrt{-1}

(13 + 4i) + n = 0

n = -(13 + 4i)

\boxed{n = -13 - 4i}

3 0
3 years ago
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If ξ={1 , 2 , 3 , . . . , 8 , 9 , 10}
DENIUS [597]

Answer:

{1,4}

Step-by-step explanation:

A={3,6,9}

B={2,3,5,7}

C={1,2,3,4,5}

AUB={2,3,5,6,7,9}

(AUB)'={1,4,8,10}

(AUB)'⋂C={1,4}

7 0
2 years ago
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Solve the equation using the zero-product property (2x-8)(7x+5)=0
Iteru [2.4K]
If xy=0 assume that x and y=0
so
(2x-8)(7x+5)=0
assume
2x-8=0 and 7x+5=0
solve each

2x-8=0
2x=8
x=4

7x+5=0
7x=-5
x=-5/7

so x=-5/7 or 4
7 0
2 years ago
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The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func
katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle (\frac{1}{3},\frac{1}4).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A(\frac{1}{3},\frac{1}4)

Let O be the origin i.e. (0,0)

Point B will be (\frac{1}{3},0)

Now, let us consider the right angled triangle \triangle OBA:

Sides:

Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}

Using Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}

sin \angle AOB = \dfrac{Perpendicular}{Hypotenuse}

\Rightarrow sin \angle AOB = \dfrac{\frac{1}{4}}{\frac{5}{12}}\\\Rightarrow sin \angle AOB = \dfrac{3}{5}

cos\angle AOB = \dfrac{Base}{Hypotenuse}

\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}

tan\angle AOB = \dfrac{Perpendicular}{Base}

\Rightarrow tan\angle AOB = \dfrac{3}{4}

cosec \angle AOB = \dfrac{Hypotenuse}{Perpendicular}

\Rightarrow cosec\angle AOB = \dfrac{5}{3}

sec\angle AOB = \dfrac{Hypotenuse}{Base}

\Rightarrow sec\angle AOB = \dfrac{5}{4}

cot\angle AOB = \dfrac{Base}{Perpendicular}

\Rightarrow cot\angle AOB = \dfrac{4}{3}

3 0
3 years ago
Please creeper keeps answering but link doesnt work plaese help
DedPeter [7]

Answer:

The answer is A: y^2/2x

Step-by-step explanation:

Hope this helps please mark brainliest  :)

6 0
2 years ago
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