Joe jumps into the water, and it takes him 5 seconds to reach the bottom of a pool 8 feet deep.

PLEASE HELP!! I WILL AWARD BRAINLIEST AND 50 POINTS!!!!!!!!!!!!!!!!!!!!!! For the given picture: a) List all of the triangles th

PIT_PIT [208]

Answer:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB. For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD. For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO. For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB. For OBF, it’s BOC and OCB

Step-by-step explanation:

There are 4 triangles. For the exterior and remote interior, I’m naming the angles with three letters. If your teacher just wants one, it would be the middle one. (I assume they’ll want all three, since the letters just name points, not angles.)

1) A) Name of triangle: ABO

B) Exterior AngleS: EAO, BOC and AOD

C) Remote Interior Angles: For EAO, it’s ABO and AOB. For BOC, it’s BAO and ABO. For AOD, it’s BAO and ABO

2) A) Name of triangle: ABC

B) Exterior Angles:EAC

C) Remote Interior Angles: ABO and BCO

3) A) Name of triangle: DOC

B) Exterior Angles: ODH, DOA, COB, and OCG

C) Remote Interior Angles: For ODH, it’s DOC and COD. For DOA, it’s ODC and DCO. For COB, it’s ODC and DCO. For OCG, it has CDO and DOC

4) A) Name Of triangle: COB

B) Exterior Angles: AOB, DOC, and OBF

C) Remote Interior Angles: For AOB, it’s OBC and OCB. For DOC, it’s OBC and OCB. For OBF, it’s BOC and OCB

6 0

3 years ago

DO ANYONE KNOW HOW TI FIND THE AREA OF A REGULAR POLYGON?? ill give brainlest and points

zloy xaker [14]

Answer:

see explanation

Step-by-step explanation:

The area (A) of a regular decagon ( 10 sided ) is calculated as

A = 0.5 × perimeter × apothem

Here side length = 3.25, hence perimeter = 10 × 3.25 = 32.5 m, thus

A = 0.5 × 32.5 × 5 = 81.25 m²

7 0

4 years ago

Read 2 more answers

A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides

ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

=(15-2x)(10-2x)x cubic inches

=(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ , here a=12, b= -100 and c=15

$x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}$

$\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}$

$\Rightarrow x=0.1528,8.18$

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, $V''|_{x=0.1528}=24(0.1528)-100$

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box has largest volume.

4 0

4 years ago

ABCDE ~ FGHIJ. Figure 2 is a dilation of figure 1, and the scale factor is 0.6. Given that FG = 12 cm, find AB.

avanturin [10]

We known that the figures are similar if and only if the corresponding sides and and angles have the common scale factor. In this item, the scale factor is 0.6. The length of AB is determined by multiplying the length of FG with the scale factor. That is,
AB = FG x scale factor
AB = (12 cm) x 0.6
AB = 7.2 cm
Thus, the length of side AB is 7.2 cm.

6 0

3 years ago

Read 2 more answers

Lynne bought a bag of grapefruit, 1 5_ 8 pounds of apples, and 2 __3 16 pounds of bananas. The total weight of her purchases was

solmaris [256]

Answer:

3 11/16 pounds

Step-by-step explanation:

Lynne bought a bag of grapefruit, 1 5/8 pounds of apples, and 2 3/16 pounds of bananas. The total weight of her purchases was 7 1/2 pounds. How much did the bag of grapefruit weigh?'

The Total weight = Weight of grape fruits + Weight of Apples + Weight of Bananas

Let the weight of the grape fruit = x

7 1/2 = x + 1 5/8 + 2 3/16

x = 7 1/2 - (1 5/8 + 2 3/16)

Lowest Common Denominator = 16

x= 7 1/2 - 3 + ( 10+ 3/16)

x = 7 1/2 - 3 + (13/16)

x = 7 1/2 - 3 13/16

Lowest Common Denominator = 16

x= 4 (8 - 13/16)

x = 4 (-5/16)

x = 3 11/16 pounds

Therefore, the bag of grapefruits weighed 3 11/16 pounds

3 0

3 years ago