Answer:
75 kgm/s
Explanation:
Impulse: This can be defined as the product of mass and change in velocity. The S.I unit is kgm/s.
From the question,
I = m(v-u)................... Equation 1
Where I = impulse, m = mass, v = final velocity, u = initial velocity.
Let the direction of the initial velocity be the positive direction.
Given: m = 5 kg, v = -10 m/s (bounce off), u = 5 m/s.
Substitute into equation 1
I = 5(-10-5)
I = 5(-15)
I = -75 kgm/s.
The negative sign tells that the impulse act in the same direction as the final velocity of the ball
Hence,
I = 75 kgm/s
Answer:
35.5KJ
Explanation:
Heat transferred (Q) = change in internal energy (∆U) + work done (W)
Q = 30KJ, W = 500Nm = 500J = 500/1000KJ = 0.5KJ
∆U = Q - W = 30 - 0.5 = 25.5KJ
∆U = final energy (U2) - initial energy (U1)
U2 = ∆U + U1 = 25.5 + 10 = 35.5KJ
P=I*E
Power (P)
Voltage (E)
<span>Amps (I)</span>
Answer:
4s
Explanation:
Using the formula of motion as follows:
V = u + at
Where;
V = final velocity (m/s)
U = initial velocity (m/s)
a = acceleration (m/s)
t = time (s)
Based on the provided information, v = 160m/s, u = 100m/s, a = 15m/s², t = ?
V = u + at
160 = 100 + 15t
160 - 100 = 15t
60 = 15t
t = 60/15
t = 4seconds.
Therefore, the time it takes for the plane to complete this increase in speed is 4s.