We want to subtract 8x + 3 from -2x+5. We can create an expression to represent this.
-2x + 5 - (8x + 3).
After this, lets distribute the - sign (think of this like expanding something with -1).
-2x + 5 - 8x - 3
Lastly, we just need to combine like terms.
-2x + 5 - 8x - 3
Combine the 5 and -3 to get 2.
-2x + 2 - 8x
Combine the -2x and -8x to get -10x.
-10x + 2
The final answer to the question is therefore A.
7/8+(−2/3) divided by 5/6
(7/8 - 2/3)/(5/6)
=(21/24 - 16/24) / (5/6)
= (5/24) / (5/6)
= 5/24 * 6/5
= 6/24
= 1/4
Answer:
3/4
pick 1,3,5 (reds) from 1,3,5,7(odd-numbered)
Given:
Right triangle
To find:
The six trigonometric functions of θ
Solution:
Hypotenuse = 18
Adjacent side to θ = 10
Opposite side to θ = ?
Using Pythagoras theorem:



Subtract 100 from both sides.

Taking square root on both sides.

Using trigonometric ratio formula:












It’s D
11x= 6x + 5x
10^2 + 6x + 5x + 3
2x(5x+3)+5x+3