Answer:
Clearly, the answer is 20/9, simplify it, and thats your answer! <3
<em>Hope that helped! <3</em>
<em>Byee!</em>
The maximum height the ball achieves before landing is 682.276 meters at t = 0.
<h3>What are maxima and minima?</h3>
Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.
We have a function:
h(t) = -4.9t² + 682.276
Which represents the ball's height h at time t seconds.
To find the maximum height first find the first derivative of the function and equate it to zero
h'(t) = -9.8t = 0
t = 0
Find second derivative:
h''(t) = -9.8
At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.
Maximum height at t = 0:
h(0) = 682.276 meters
Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.
Learn more about the maxima and minima here:
brainly.com/question/6422517
#SPJ1
top left: speed = 2.7 miles per hour = 2.7 MPH
top right: speed = 0 miles per hour = 0 MPH
bottom left: speed = 4 miles per hour = 4 mi/h
bottom right: speed = 2 miles per hour = 2 mi/h
and so, the fastest is bottom left. And pay attention in class! i'm in highschool and Iearned this in 6th grade!
Step-by-step explanation:
key: speed= distance/time
distance= speedxtime
time=distance/speed
top left: 8/3= 2.66667 MPH= 2.7 MPH
top right: 0/8= 0 MPH= 0 MPH
bottom left: 8/2= 4 MPH= 4 MPH
bottom right: 8/4= 2 MPH= 2 MPH
Answer:
-348.33
Step-by-step explanation:
Use PEMDAS as your guide.
(-342-8) - (-5/2+1)
PEMDAS
parenthesis
-350 - (-5/3)
PEMDAS
Dvisision
-350- (-1.67)
= - 348.33
Hope this is what your looking for!
