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3 years ago

A radio is being discounted 40%. If the sale price of the radio is $31.02, what was the original price of the radio?

Mathematics

1 answer:

kobusy [5.1K]3 years ago

8 0

Answer:

$51.70 is the original price

Step-by-step explanation:

Step 1:

Turn 40% into a decimal which makes it 0.40

ex. 50% would be 0.50, 5% would be 0.05 etc.

Step 2:

Put the numbers into this formula: Original Price (x) - Percent Off times Original Price = Sales Price

x - 0.40x = 31.02 this is basically 1x - 0.40x = 31.02 so,

Solving the left side of our equation gives us 1x - 0.40x = 0.60x

so now you have: 0.60x = 31.02

Step 3:

Divide both sides by 0.60 which gets x by itself and gives us the original price which is $51.70

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The original quantity is 20 and the new quantity is 15. Adam incorrectly says the percent decrease is about 14.29%. What is the

Yuki888 [10]

Answer: A. divided the difference of the two quantities by the sum of the two quantities.

===================================================

Explanation:

The difference of the quantities is 20-15 = 5

The sum of the quantities is 20+15 = 35

Dividing those results leads to 5/35 = 0.142857 which rounds to 0.1429

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This is likely the path Adam took. This path is incorrect. The correct steps are shown below

---------------------

Difference = 20-15 = 5

Divide the difference over the original quantity

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We have a 25% decrease because the new quantity (15) is smaller than the old quantity (20)

----------------------

Here's another way to approach the problem

A = old value = 20

B = new value = 15

C = percent change

C = [ (B-A)/A ] * 100%

C = [ (15-20)/20 ] * 100%

C = (-5/20)*100%

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Answer:

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Step-by-step explanation:

The given limits are;

$\lim_{x \to 4} f(x) =5$ , $\lim_{x \to 4} g(x) =0$ and $\lim_{x \to 4} h(x) =-2$

We want to find

$\lim_{x \to 4} \frac{f}{g}(x)= \lim_{x \to 4} \frac{f(x)}{g(x)}$

By the properties of limits, we have;

$\lim_{x \to 4} \frac{f}{g}(x)= \frac{\lim_{x \to 4} f(x)}{\lim_{x \to 4} g(x)}$

This gives us;

$\lim_{x \to 4} \frac{f}{g}(x)= \frac{5}{0}$

Division by zero is not possible. Therefore the limit does not exist.

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