Jason: 5/7
Sara: 4/5
Think of it this way: if the total track is a mile, and Jason runs 5/7 of it,  he has run 5/7 of a mile. Then Sara runs 4/5 OF 5/7, with "of" meaning "times," so she runs 4/5 x 5/7, which gives you 20/35, which simplifies to 4/7. You can also think of Sara's distance as 80 percent of Jason's. If she runs "80 percent of the sevenths that Jason ran," that means she ran 4 out of his 5 sevenths.
        
             
        
        
        
Answer: make 6 jumps which are 0.4 long to get 2.4
Step-by-step explanation:
 
        
             
        
        
        
Answer:
26.5 units²
Step-by-step explanation:
I am splitting the figure into a rectangle and two triangles to make this easier for me.
The rectangle is b•h so 5•4 = 20 units²
Area of triangle=1/2bh
The left triangle is  (3•3) --->
(3•3) --->  (9) ---> 4.5 units²
(9) ---> 4.5 units²
The right triangle is  (2•2) --->
(2•2) ---> (4) ---> 2 units²
(4) ---> 2 units²
Then add it all up: 20+4.5+2 = <u>26.5</u><u> </u><u>units²</u>
 
        
             
        
        
        
Answer:
Step-by-step explanation:
A(x1,y1)     B(x2,y2)    
M(x,y)  =>   x= and y=
 and y=
-----------------------------------------------------------
A(15,-11)   B(-10,10)
M( ,
, )=(
)=( ,
, )
)
 
        
             
        
        
        
If α and β are the Roots of a Quadratic Equation ax² + bx + c then :
✿  Sum of the Roots : α + β 
✿  Product of the Roots : αβ 
Let the Quadratic Equation we need to find be : ax² + bx + c = 0
Given : The Roots of a Quadratic Equation are 6 and 3
⇒ α = 6 and β = 3
Given : The Leading Coefficient of the Quadratic Equation is 4
Leading Coefficient is the Coefficient written beside the Variable with Highest Degree. In a Quadratic Equation, Highest Degree is 2
Leading Coefficient of our Quadratic Equation is (a)
⇒ a = 4
⇒ Sum of the Roots 
⇒ -b = 9(4)
⇒ b = -36
⇒ Product of the Roots 
⇒ c = 18 × 4
⇒ c = 72
⇒ The Quadratic Equation is 4x² - 36x + 72 = 0