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Aleks04 [339]
3 years ago
12

URGENT PLEASE HELP (15 POINTS!!!!!!)

Mathematics
2 answers:
faust18 [17]3 years ago
3 0

Answer:

connect C and E with a straightedge

Step-by-step explanation:

Nikitich [7]3 years ago
3 0

Answer:

The answer is option C

Step-by-step explanation:

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Jason ran 5/7 of the distance around the school track. Sara ran 4/5 of Jason's distance. What fraction of the total distance aro
masha68 [24]
Jason: 5/7
Sara: 4/5

Think of it this way: if the total track is a mile, and Jason runs 5/7 of it,  he has run 5/7 of a mile. Then Sara runs 4/5 OF 5/7, with "of" meaning "times," so she runs 4/5 x 5/7, which gives you 20/35, which simplifies to 4/7. You can also think of Sara's distance as 80 percent of Jason's. If she runs "80 percent of the sevenths that Jason ran," that means she ran 4 out of his 5 sevenths.
7 0
3 years ago
Ill give correct one brainliest
adelina 88 [10]

Answer: make 6 jumps which are 0.4 long to get 2.4

Step-by-step explanation:

4 0
3 years ago
56 POINTS! Find the area of the following figure. Explain how you got your answer.
AleksAgata [21]

Answer:

26.5 units²

Step-by-step explanation:

I am splitting the figure into a rectangle and two triangles to make this easier for me.

The rectangle is b•h so 5•4 = 20 units²

Area of triangle=1/2bh

The left triangle is \frac{1}{2}(3•3) ---> \frac{1}{2}(9) ---> 4.5 units²

The right triangle is \frac{1}{2}(2•2) --->\frac{1}{2}(4) ---> 2 units²

Then add it all up: 20+4.5+2 = <u>26.5</u><u> </u><u>units²</u>

3 0
2 years ago
Which are the coordinates of the midpoint of the segment connecting(15,-11) and (-10,10)
saveliy_v [14]

Answer:

Step-by-step explanation:

A(x1,y1)     B(x2,y2)    

M(x,y)  =>   x=\frac{x1+x2}{2} and y=\frac{y1+y2}{2}

-----------------------------------------------------------

A(15,-11)   B(-10,10)

M(\frac{15-10}{2},\frac{-11+10}{2})=(-\frac{5}{2},-\frac{1}{2})

7 0
3 years ago
Write the quadratic equation whose roots are 6 and 3, and whose leading coefficient is 4
nekit [7.7K]

If α and β are the Roots of a Quadratic Equation ax² + bx + c then :

✿  Sum of the Roots : α + β \mathsf{= \frac{-b}{a}}

✿  Product of the Roots : αβ \mathsf{= \frac{c}{a}}

Let the Quadratic Equation we need to find be : ax² + bx + c = 0

Given : The Roots of a Quadratic Equation are 6 and 3

⇒ α = 6 and β = 3

Given : The Leading Coefficient of the Quadratic Equation is 4

Leading Coefficient is the Coefficient written beside the Variable with Highest Degree. In a Quadratic Equation, Highest Degree is 2

Leading Coefficient of our Quadratic Equation is (a)

⇒ a = 4

⇒ Sum of the Roots \mathsf{: (6 + 3) = \frac{-b}{4}}

⇒ -b = 9(4)

⇒ b = -36

⇒ Product of the Roots \mathsf{: (6 \times 3) = \frac{c}{4}}

⇒ c = 18 × 4

⇒ c = 72

⇒ The Quadratic Equation is 4x² - 36x + 72 = 0

8 0
3 years ago
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