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3 years ago

5

HEELLLLPPPP!!!! If the inverses of two functions are both functions, will the inverse of the composite function made by the orig

inal functions also be a function?? I really need help

1 answer:

Anon25 [30]3 years ago

8 0

I pretty shure its true

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Alguien me me ayude hacer mi tarea?

Dafna11 [192]

Answer:

speack engliush please

Step-by-step explanation:

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3 years ago

Rachel has a bag that contains a total of 224 red and yellow candies. The ratio of red candies, R , to yellow candies, Y , is 3

julia-pushkina [17]

Answer:

96 red

Step-by-step explanation:

96 red, 128 yellow; 3/4=.75; r+y=224; .75y+y=224; 1.75y=224; 224/1.75=128, 224-128=96

3 0

3 years ago

Use rounding to estimate 2.57 +0.14

marin [14]

2.57=3
+0.14=0
———
2.71=3

3 0

3 years ago

Read 2 more answers

Identify the quotient in the form a + bi. HELP ASAP PLEASE!!

Step2247 [10]

Solving the expression $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

So, Option A is correct.

Step-by-step explanation:

We need to solve the expression: $\frac{4-5i}{2+3i}$

Multiplying and dividing by 2-3i

$=\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}\\=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,know\,\, i^2=-1\\=\frac{8-12i-10i+15(-1)}{4-9(-1)}\\=\frac{8-15-12i-10i}{4+9}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}$

So, solving the expression $\frac{4-5i}{2+3i}$ we get $-\frac{7}{13}-\frac{22i}{13}$

So, Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

#learnwithBrainly

8 0

3 years ago

Simplify<br> 4-3[6-2(4-3)]

ikadub [295]

Answer:

<h2>-8</h2>

Step-by-step explanation:

$4-3[6-2(4-3)]\\\\Follow\:the\:PEMDAS\:order\:of\:operations\\\\\mathrm{Calculate\:within\:parentheses}\:\left[6-2\left(4-3\right)\right] : 4\\\\=4-3\times\:4\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:3\times\:4\::\quad 12\\=4-12\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:4-12\:\\\\:\quad -8$

4 0

3 years ago