<span>y=x+16
y=-x+4
All you have to do is substitute.
Put the second equation into the first equation.
-x + 4 = x + 16
4 = 2x + 16
-12 = 2x
-6 = x
Now substitute the x into one of the equations to get y.
y = (-6) + 16
y = 10
The solution to these equations is (-6, 10).</span>
Answer:
2/15
Step-by-step explanation:
Given that :
pretzel = 4
Popcorn = 3
Cheddar cracker = 3
Total = 4 + 3 + 3 = 10
Probability = Required outcome / Total possible outcomes
Selecting with replacement :
First selection :
P(pretzel bag) = 4 / 10
Second selection :
P(pretzel bag) = 3 / 9
P(2 pretzel bags) = 4/10 * 3/9 = 12 / 90 = 2/15
The inverse will be 2x+3/4 or D in your picture
Answer:
Step-by-step explanation:
Both expressions are examples of the <em>distributive property</em>, which basically says "if I have <em>this </em>many groups of some size and <em>that</em> many groups of the same size, I've got <em>this </em>+ <em>that</em> groups of that size altogether."
To give an example, if I've got <em>3 groups of 5 </em>and <em>2 groups of 5</em>, I've got 3 + 2 = <em>5 groups of 5 </em>in total. I've attached a visual from Math with Bad Drawings to illustrate this idea.
Mathematically, we'd capture that last example with the equation
. We can also read that in reverse: 3 + 2 groups of 5 is the same as adding together 3 groups of 5 and 2 groups of 5; both directions get us 8 groups of 5. We can use this fact to rewrite the first expression like this: 
.
This idea extends to subtraction too: If we have 3 groups of 4 and we take away 1 group of 4, we'd expect to be left with 3 - 1 = 2 groups of 4, or in symbols: 
. When we start with two numbers like 15 and 10, our first question should be if we can split them up into groups of the same size. Obviously, you could make 15 groups of 1 and 10 groups of 1, but 15 is also the same as <em>3 groups of 5</em> and 10 is the same as <em>2 groups of 5</em>. Using the distributive property, we could write this as 
, so we can say that 
.
Answer:
sorry bro but i suck at math
Step-by-step explanation:
good luck tho =)
