Move the -5 over by adding 5 to both sides
3x^2+4x+5=0
must use quadratic formula
for an equation in the form
ax^2+bx+c=0
x=
a=3
b=4
c=5
x=
x=
x=
x=
remember that√-1=i
x=
x=
x=
or x=
Answer:
y=0.5x + 5
Step-by-step explanation:
The points are (0,5) and (-10,0)
to find the slope do
0-5/-10-0 = 5/10 = 1/2 = 0.5
next plug one of the points into point slope formula
y-y1=m(x-x1)
lets use the point (-10,0)
y1=0
x1= -10
m= 0.5
y-0=0.5(x- -10)
y = 0.5(x+10)
distribute the 0.5
y=0.5x+5
Answer:
Model B has 6 shaded sections
Step-by-step explanation:
The question is not complete. The complete question should be in the form:
Victor has 2 fraction models. Each is divided into equal sized sections the models are shaded to represent the same fraction. Model A is divided into 6 sections and 3 sections are shaded. Model B is divided into 12 sections. What do you know about the number of sections shaded in Model B? Explain your answer.
Solution:
The fraction modeled by model A is given by the ratio of shaded sections to the total number of sections.
That is Fraction of model A = number of shaded sections / total number of sections.
Hence:
Fraction of model A = 3 / 6
Since model B and Model A are equivalent, the number of shaded sections in Model A is given by:
number of shaded sections in model B/ total number of sections in model B = Fraction of model A
number of shaded sections in model B / 12 = 3 / 6
number of shaded sections in model B = 12 * 3/6
number of shaded sections in model B = 6
I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
The answer is a i believe
you can solve it
