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It should be noted that a good that has a high demand elasticity for an economic variable implies that consumer demand for that good is more responsive to changes in the variable.
<h3>How to explain the demand?</h3>
It should be noted that an elastic demand is one werr the change in quantity demanded due to a change in price is large.
Also, an inelastic demand is one in which the change in quantity demanded due to a change in price is small. When the formula creates an absolute value greater than 1, the demand is elastic.
Here, a good that has a high demand elasticity for an economic variable implies that consumer demand for that good is more responsive to changes in the variable.
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The current function equation is Y=1/3|x|
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The meaning relative f(x) = is the absolute value and is weighted by a factor 3 vertically.
If a constant (say a) multiplies the function, the parent will be extended vertically.
We have below vertical extension and compression conditions.
A > 1 = > spread vertically
0 < < 1 = > compression vertically
Therefore we will subtract the entire feature by 1/3 for vertical compression by a factor of 3.
The equation for the current function is then Y=1/3|x|
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<em>Hope this helps!</em>
<em />
<u>Brainliest would be great!</u>
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<u><em>With all care,</em></u>
<u><em>07x12!</em></u>
<h3>
Answer:</h3>
- Find the composite of the functions
- x/3
- All the answers are correct
- f(x) = 2+∛(x/3)
- f(x) = (x+3)/2
<h3>
Step-by-step explanation:</h3>
1. If f(x) and g(x) are inverse functions, then f(g(x)) = g(f(x)) = x. Finding the composite of the two functions will tell you if they are inverses.
2. To find the inverse of a function, swap x and y, then solve for y.
... x = 3y
... x/3 = y . . . . . matches f(x) = x/3
3. A function will pass the vertical line test. If its inverse is also a function, that, too, will pass the vertical line test. Since the inverse of a function is that function reflected across y=x, any inverse function that passes the vertical line test corresponds to an original function that passes the horizontal line test. (A vertical line reflected across y=x is a horizontal line.)
4. See 2.
... x = 3(y -2)³
... (x/3) = (y -2)³ . . . . divide by 3
... ∛(x/3) = y -2 . . . . .take the cube root
... 2+∛(x/3) = y . . . . .add 2
... f(x) = 2+∛(x/3) . . . . is the inverse
5. See 2.
... x = 2y -3
... x+3 = 2y . . . . . add 3
... (x+3)/2 = y . . . .divide by 2
... f(x) = (x+3)/2 . . . . is the inverse