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2 years ago

The rug has an area of 20 square meters. The width of the rug is 4 meters

Mathematics

2 answers:

Rina8888 [55]2 years ago

7 0

Answer: The width of the rug is 5 meters
Explanation: 4•5=20

BartSMP [9]2 years ago

3 0

Answer:

<h3>Length = 5 m</h3>

Step-by-step explanation:

area = length x width

where area = 20 m²

width = 4 m

length = ?

plugin values into the formula:

A = L * W

20 = L * 4

L= 20 / 4

L = 5 m

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In AEFG, F = 61 inches, ZF=79º and ZG=34°. Find the length of g, to the nearest 10th of an inch.

DENIUS [597]

Answer:

g ≈ 34.7 in

Step-by-step explanation:

The law of sines is useful for this:

f/sin(F) = g/sin(G)

Multiplying by sin(G), we have ...

g = f·sin(G)/sin(F) = (61 in)·sin(34°)/sin(79°)

g ≈ 34.7 in

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2 years ago

Using the given information, give the vertex form equation for each parabola.

ollegr [7]

Answer:

Step-by-step explanation:

If you plot this point and the directrix on a coordinate plane, you can see that the directrix is 1/4 of a unit below the vertex. Since, by nature, a parabola opens in the direction opposite the directrix and "hugs" the focus, this is a positive x-squared parabola (meaning it opens upwards). The formula for this type of a parabola is, in vertex form,

$4p(y-k)=(x-h)^2$

where p is distance (in units) between the vertex and the directrix and h and k are the coordinates of the vertex. For us, p = .25, h = 7, and k = -6. Filling in our formula:

$4(.25)(y+6)=(x-7)^2$

Simplify the left side to

$1(y+6)=(x-7)^2$ which simplifies, in its entirety, to

$(x-7)^2-6=y$

3 0

2 years ago

Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the

Rama09 [41]

Question:

Britney throws an object straight up into the air with an initial velocity of 27 ft/s from a platform that is 10 ft above the ground. Use the formula h(t)=−16t2+v0t+h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground?

1s 2s 3s 4s

Answer:

It takes 2 seconds for object to hit the ground

Solution:

The given equation is:

$h(t) = -16t^2 + v_0t+h_0$

Initial velocity = 27 feet/sec

$h_0 = 10\ feet$

Therefore,

$h(t) = -16t^2 +27t+10$

At the point the object hits the ground, h(t) = 0

$-16t^2 +27t+10 = 0\\\\16t^2-27t-10=0$

Solve by quadratic formula,

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=16,\:b=-27,\:c=-10:\quad \\\\t=\frac{-\left(-27\right)\pm \sqrt{\left(-27\right)^2-4\cdot \:16\left(-10\right)}}{2\cdot \:16}\\\\t = \frac{27 \pm \sqrt{1369}}{32}\\\\t = \frac{27 \pm 37}{32}\\\\We\ have\ two\ solutions\\\\t = \frac{27+37}{32}\\\\t = \frac{64}{32}\\\\t = 2\\\\And\\\\t = \frac{27-37}{32}\\\\t = -0.3125$

Ignore, negative value

Thus, it takes 2 seconds for object to hit the ground

7 0

3 years ago

A student took two national standardized tests while applying for college. On the first test,

kvv77 [185]

Answer:

Step-by-step explanation:

4 0

2 years ago

What's the answer ???????

Tatiana [17]

A²+b²=c²
64+b²=196
b²=132
b=11.48912529

8 0

3 years ago