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tino4ka555 [31]
3 years ago
11

( 0) + ( -8) + (+4) = ( 0) + ( -3) + ( -4) =

Mathematics
2 answers:
sukhopar [10]3 years ago
8 0

Answer:

1. -4

2. -7

(don't quote the 0)

Mekhanik [1.2K]3 years ago
3 0

Answer:

1) -4

2) -7

Step-by-step explanation:

1) 0 + (-8) + 4 =

0 - 8 + 4 =

-8 + 4 =

= -4

2) 0 + (-3) + (-4) =

0 - 3 - 4 =

= -7

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A box contains five ping-pong balls, each with a number written on it. One ball has a one painted on it, one ball has a four, tw
Temka [501]

Answer:

0

Step-by-step explanation:

Numbers on balls:

1, 4, 7, 7, 8

Try to find the sum of all numbers:

1+4+7+7+8 = 27

According to the rule of 3, any number is dividable by 3 if the sum of it's individual is divided by 3.

27 is dividable by 3, therefore any combination will result a number with a factor of three.

Prime number is the number that is only dividable by 1 and itself. Therefore, any combination using those numbers are not prime number.

So the probability is 0

4 0
3 years ago
16 2/3% of what number is 90?
zysi [14]

Answer:

540

Step-by-step explanation:

90 is 16 2/3% of 540

7 0
3 years ago
One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

5 0
3 years ago
What is <br> 162divide[6 multiply (7-4) to the second power]<br> help please
Setler [38]

Answer:

please mark me brainlist

Step-by-step explanation:

i need it

3 0
2 years ago
In the xy-plane, the equations x + 2 = 10 y and 3 +6 = x y c represent the same line for some constant c. What is the value of c
aalyn [17]

Answer:

C=30

Step-by-step explanation:

Supposing that we have the lines

x+2=10y

and

3x+6=Yc.

Note that dividing by 3 the second line can be rewritten as

x + 2= Y c/3.  

Remember that a line is written as ax+b=dY, in our case, both lines have a=1 and b=2. Therefore, in orther that the two lines are equal, we need that 10=c/3, hence c=30.

3 0
3 years ago
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