An isotope of any element is the same, with a variation in the neutrons of the nucleus.
The mass number change but the atomic number doesn't.
In this case, protium, deuterium, and tritium are all hydrogen isotopes.
Protium is 1H or Hydrogen-1 is without neutrons.
Deuterium is 2H or Hydrogen-2 has one neutron.
Tritium is 3H or Hydrogen-3 has two neutrons.
Answer AND Explanation:
There is a large number of biochemical reactions taking place in a cell at any given time. Enzymes being biological catalysts control these reactions and regulate them so that they proceed at a pace that is suitable for sustaining life. Thus enzymes regulate cellular activities. Enzymes also ensure that only the required reactions take place and progress to their appropriate extent.
If a plant cell had a mutation such that the cyclic electron flow is observed at a much higher rate, which photosystem is most likely mutated such that energy is absorbed at a lower rate?
PSI
PSII
Answer:
PSII
Explanation:
Non-cyclic phosphorylation involves both PSI and PSII. The process starts with the splitting of water and excitation of electrons of the reaction center of PSII upon the absorption of solar energy at the wavelength of 680 nm. Any mutation in PSII would not allow the non-cyclic phosphorylation to occur when only cyclic phosphorylation would occur. The process of cyclic phosphorylation includes only PS I. Its reaction center absorbs maximum light at 700 nm and is cycled back while supporting ATP synthesis. Therefore, if a plant performs cyclic phosphorylation at a higher rate and absorbs less energy, this means that mutation was in PSII.
im not even sure tbh these are really hard im so sorry
