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Norma-Jean [14]
3 years ago
12

Quadrilateral RPQS is a rectangle. Label the missing measures.

Mathematics
1 answer:
Taya2010 [7]3 years ago
7 0

Answer:

Part 1) PR=9\ units

Part 2) PQ=12\ units

Part 3) PS=15\ units

part 4) QR=15\ units

Part 5) RT=7.5\ units

Step-by-step explanation:

we know that

In a rectangle opposite sides are parallel and congruent

The measure of each interior angle is 90 degrees

The diagonals are congruent and bisect each other

step 1

Find the length of side PR

we know that

PR=QS ----> by opposite sides

we have

QS=9\ units

therefore

PR=9\ units

step 2

Find the length of side PQ

we know that

PQ=RS ----> by opposite sides

we have

RS=12\ units

therefore

PQ=12\ units

step 3

Find the length of diagonal PS

we know that

PS=2PT---> the diagonals bisect each other

we have

PT=7.5\ units ---> given problem

therefore

PS=2(7.5)=15\ units

step 4

Find the length of diagonal QR

we know that

QR=PS---> the diagonals are congruent

we have

PS=15\ units

therefore

QR=15\ units

step 5

Find the length of RT

we know that

QR=2RT---> the diagonals bisect each other

we have

QR=15\ units

substitute

15=2RT\\RT=7.5\ units

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Answer:

The answer to your question is: 3600 cm ²

Step-by-step explanation:

Rectangular box:

length = 40 cm

breadth = 25

height = 20 cm

Area =

Area of the base = 40 x 25 = 1000 cm²

Area of the lateral sides = 2(40 x 20) = 1600 cm²

Area of the sides = 2(25 x 20) = 1000 cm²

Total area = 1000 + 1600 + 1000 = 3600 cm²

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3 years ago
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6 0
3 years ago
2(a³+b²+11)+1(3+a³+b+11)
Ann [662]

Answer:

2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

2(a^3+b^2+11)+1(3+a^3+b+11)

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14

Therefore, 2(a^3+b^2+11)+1(3+a^3+b+11) is equal to:

2a^3+2b^2+22+a^3+b+14

Now, combining like terms using the commutative property of addition, we get:

=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36

Therefore, the simplified form is 3a^3+2b^2+b+36

8 0
4 years ago
How to solve negative exponents? (Extended,long)
defon
Easily, you write the inverse of it without a minus
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Good Luck

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4 0
3 years ago
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