It might be to late but the answer is C
The work done to "HOLD" a load of bricks at any height is zero.
Work is done only when force acts through a DISTANCE.
The work done to LIFT 30 kg of anything to 20m higher than
it already is, is
(force) · (vertical distance)
= (mass) · (gravity) · (vertical distance)
= (30 kg) · (9.8 m/s²) · (20 m)
= 5,880 joules
Answer:
The Fermi energy is 0.568 eV and the conductivity at room temperature is 31.24 (Ωcm)⁻¹
Explanation:
Data given:
Nd = doping concentration = 5x10⁶/cm³
According the mass action law, the hole concentration is:



The conductivity of n-type of semi-conductor is equal to:
The mobility of Germanium is 3900 cm²/Vs
σ = 1.6x10⁻¹⁹ * 5x10¹⁶ * 3900 = 31.24 (Ωcm)⁻¹
Answer:
body measurements are a common method specifying body proportion for the purpose of fitting clothes.
3.5m is ur answer ask for more questions anytime