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dimulka [17.4K]

3 years ago

7

A balloon contains 0.04m3 of air at a pressure of 1.20 x 105Pa. Calculate the pressure required to reduce its volume to 0.025m3

at constant temperature.

1 answer:

sdas [7]3 years ago

4 0

Answer:

you can simply answer p1v1=p2v2 p2 = p1v1÷ p2 then inter what given in the formula you get it pl=1.20x 105pa vl= 0.40m3 v2=0.025m3

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3 years ago

Jim pushes hard on a rock that weighs 500 pounds. He pushes with a force of 50 pounds, but the rock doesn't move. How much work

seraphim [82]

Answer:

Zero work

Explanation:

Recall that work done on an object is defined as the product of the net force applied to an object times the distance it travels in the same direction as the force.

Since in this case Jim used a given force to push a rock, but it didn't move, then he did zero work (because the distance moved is zero).

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Suppose you are helping Galileo measure the acceleration due to gravity by dropping a canon ball from the tower of Pisa, You mea

Anni [7]

It is given that the height of the tower is

$h=183 ft.$

The uncertainty the measurement of this height is

$\Delta h=0.2 ft$

Drop time is measured as:

$t=3.5s$

The uncertainty in measurement of time is:

$\Delta t=0.5 s$

Using the equation of motion: $h=ut+\frac{1}{2} at^2$ where, $h$ is the distance covered, $u$ is the initial velocity, $a$ is the acceleration and $t$ is the time.

$u=0$ (because canon ball is in free fall). we need to calculate the value of a=g.

$\Rightarrow h=\frac{1}{2}gt^2$

$\Rightarrow g=\frac{2h}{t^2}\\ \Rightarrow g=\frac{2\times 183ft}{(3.5s)^2}=29.87 ft/s^2$

The uncertainty in this value is given by:

$\Delta g=g\sqrt{(\frac{\Delta h}{h})^2+(\frac{2\Delta t}{t})^2}$

Substitute the values:

$\Delta g=29.87\sqrt{(\frac{0.2 }{183})^2+(\frac{2\times 0.5}{3.5})^2}=29.87\sqrt{1.19\times 10^{-6}+0.08}=29.87\times \sqrt{0.08}=29.87\times 0.28=8.44 ft/s^2$

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4 years ago

While discussing electronic gasoline injection systems, Technician A states that most multiport EFI systems use two injectors fo

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Answer:Technician B is right.

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8 0

4 years ago

Directions: Analyze and illustrate the given problems. Show your mathematical equations.

Vitek1552 [10]

Answer:

1. 2160 J

2. 2940 J

3. 64 J

Explanation:

1. Determination of the work done.

Weight (W) = 180 N

Height (h) = 12 m

Workdone =?

Wd = W × h

Wd = 180 × 12

Wd = 2160 J

Thus, the Workdone is 2160 J

2. Determination of the work done.

Mass (m) = 50 Kg

Height (h) = 6 m

Acceleration due to gravity (g) = 9.8 m/s²

Workdone =?

Wd = mgh

Wd = 50 × 9.8 × 6

Wd = 2940 J

Thus, the Workdone is 2940 J

3. Determination of the work done.

Force (F) = 16 N

Distance (d) = 4 m

Workdone =?

Wd = F × d

Wd = 16 × 4

Wd = 64 J

Thus, the Workdone is 64 J

8 0

3 years ago