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scoundrel [369]
3 years ago
14

Can someone please help me?

Physics
1 answer:
IRINA_888 [86]3 years ago
7 0
It might be to late but the answer is C
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2 years ago
Water flows into a horizontal, cylindrical pipe at 1.4 m/s. the pipe then narrows until its diameter is halved. what is the pres
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\Delta P= \frac{1}{2} \rho ( v^2_{2} - v^2_{1} )

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v_{1} A_{1} = v_{2} A_{2}.

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\Delta P= \frac{1}{2} \rho ( v^2_{2} - v^2_{1} )=\frac{1}{2}\times 1000 kg/m^3(5.6^2-1.4^2)\\\\ \Delta P = 14700\ Pa

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