3 years ago

Can someone please help me?

Physics

1 answer:

IRINA_888 [86]3 years ago

7 0

It might be to late but the answer is C

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kodGreya [7K]

Answer:

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We have expression for sound intensity level,

$L=10log_{10}\left ( \frac{I}{I_0}\right )$

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$\frac{70}{40}=\frac{10log_{10}\left ( \frac{I_1}{I_0}\right )}{10log_{10}\left ( \frac{I_2}{I_0}\right )}\\\\\frac{7}{4}=\frac{log_{10}\left ( \frac{I_1}{I_0}\right )}{log_{10}\left ( \frac{I_2}{I_0}\right )}\\\\10^7\frac{I_2}{I_0}=10^4\frac{I_1}{I_0}\\\\\frac{I_1}{I_2}=10^3=1000$

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3 years ago

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