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devlian [24]
3 years ago
5

The work done in holding a 30kg of bricks to a height of 20m is

Physics
1 answer:
ella [17]3 years ago
8 0
The work done to "HOLD" a load of bricks at any height is zero.
Work is done only when force acts through a DISTANCE.

The work done to LIFT 30 kg of anything to 20m higher than
it already is, is

(force) · (vertical distance)

= (mass) · (gravity) · (vertical distance)

= (30 kg) · (9.8 m/s²) · (20 m)

= 5,880 joules
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1) X-component: 568.5 N, Y-component: 511.9 N

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Explanation:

1)

In this first part of the problem, we have to resolve the force into its two components, along the x and the y direction.

The two components are given by:

F_x = F cos \theta\\F_y = F sin \theta

where

F = 765 N is the magnitude of the force

\theta=42.0^{\circ} is the angle of the force with the horizontal

Substituting, we find:

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2)

First of all, we have to find the horizontal component of the pulling force, which is given by

F_x = F cos \theta

where

F = 100 N is the magnitude of the pulling force

\theta=30.0^{\circ} is the direction of the force with the horizontal

Substituting,

F_x = (100)(cos 30^{\circ})=86.6 N

Now we can find the acceleration of the wagon by using Newton's second law:

F_x = ma_x

where

F_x = 86.6 N is the net force in the horizontal direction

m = 100 kg is the mass of the wagon

a_x is the acceleration in the horizontal direction

Solving for a_x, we find

a_x = \frac{F_x}{m}=\frac{86.6}{100}=0.87 m/s^2

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brainly.com/question/2678571

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