We simply use the formula,
Given, velocity = 4 m per s and distance = 120 m.
Substituting these values, we get
.
Thus, required time for the elevator in order to travel 120 m upwards is 30 s.
A certain wave motion has a frequency of 10 cycles / s and a wavelength of 3 m. so its propagation speed is
1 answer:
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Answer:
- 256 lbs
Explanation:
The internal axial load at point D can be calculated as the change in the subjected loads. if the magnitude of the horizontal direction = zero
; Then:
internal axial load at point D = Δ P
= -(P₂ - P₁)
= - ( 888 lbs - 632 lbs)
= - 256 lbs