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ratelena [41]
3 years ago
5

You are out in your sail-boat and the wind stops blowing when you arr 20 meters from shore- you are stuck. You have no paddles i

n the boat and are not able to reach the water to push with your body use Newton's third law of motion to identify what you can do to get to shore using the box of apples you find in the boat
Physics
1 answer:
monitta3 years ago
5 0

Answer:

According to Newton's third law, throwing the apples in the opposite direction to the shore with a force, F₁, one after the other, repeatedly, pushes the both towards the shore with a force also equal to F₂ until the boat reaches the shore

Explanation:

The given parameters are;

The distance of the boat from the shore = 20 meters

The available propulsion devices = A box of apples

According to Newton's third law of motion states that action and reaction are equal and opposite

Therefore, according to Newton's third law, by throwing the apple into the  water in the opposite direction to the shore, such that each apple of mass m₁, is given an acceleration a₁, will result in a force, F₁ = m₁a₁ in the direction away from the shore

According to Newton's third law of motion, the force F₁, will result in an opposite reaction force F₂ in the direction of the shore, such that as F₁ is made large by giving a higher acceleration, a₁ the apples, reaction force on the occupant of the boat , who is throwing the apple, F₂, increases

F₁ = -F₂

Where;

F₂ = m₂·a₂

a₂ = The acceleration of the boat and the occupant

m₂ = The mass of the boat and the occupant

Given that the mass, m₂, is constant, the acceleration of the boat and occupant, a₂, increases as F₁ increases, increasing the speed of the boat from zero to positive value above zero m/s and the boat moves towards the shore

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Ipatiy [6.2K]

Answer:

It is found that W1 - W2 loss in weight of solid when immersed in water is equal to the weight of the water displaced by the body. This verifies Archimedes' principle.

6 0
3 years ago
A. Draw the electric field lines around a negative charge.
Alborosie
<h2>a. Answer:</h2>

We use Electric field lines for visualizing electric  fields, so this helps us to see the problem more real. So an electric field line is an imaginary  line or curve drawn through a region of space such that the tangent at any point comes from the direction of the electric-field vector at that point. The electric field lines around a negative charge is shown in the First figure below.

<h2>b. Answer:</h2>

Electric forces can be found by using the Coulomb Law's that states <em>that The magnitude of the electric force between two point charges is directly proportional  to the product of the charges and inversely proportional to the square  of the distance between them. </em>This can be expressed as follows:

F=k\frac{\left | q_{1}q_{2} \right |}{r^2} \\ \\ Where: \\ \\ k=9\times 10^9Nm^2/c^2 \\ \\ q_{1}=0.00150 C \ and \ q_{2}=0.00240 C \\ \\ r=0.900 m

Then:

F=9\times 10^9\frac{\left | 0.00150 \times 0.00240 \right |}{(0.900)^2} \\ \\ \therefore \boxed{F=40000N}

This force is repulsive because the two charges are positive and recall that two positive charges or two negative charges repel each other while a positive charge  and a negative charge attract each other.

<h2>C. Answer:</h2>

From the statement, we have two charged objects. Let's say that this charges are:

q_{1} \ and \ q_{2}

If the amount of charge on one of the objects is tripled, let's say this is the charge q_{2}, then the new charge is:

q_{N}=3q_{2}

In the formula of Coulomb:

F=k\frac{\left | q_{1}q_{N} \right |}{r^2} \\ \\ \therefore F=k\frac{\left | q_{1}(3q_{2}) \right |}{r^2} \\ \\ \therefore \boxed{F=3k\frac{\left | q_{1}q_{2} \right |}{r^2}}

<em>The conclusion is that if the amount of charge on one of the objects is tripled, the electric force between two charged objects is also tripled</em>

<h2>d. Answer:</h2>

Let's use the Coulomb's Law again to solve this problem. We want to know how the electric force between two charged objects changes if the charges are moved closer together:

F=k\frac{\left | q_{1}q_{N} \right |}{r^2}

<em>By saying that the charges are moved closer together, we want to express that r becomes smaller. Since r is in the denominator, this implies that the electric force between these two charged objects becomes greater.</em>

<h2>e. Answer:</h2>

From the figure, we can see a metal sphere on a stand. There we have both positive and negative charges. We can say that the positive charge of this sphere is +10q and the negative and the negative charge is -10q. Since the electric charge is conserved, then the algebraic sum of all the electric charges in any closed system is constant. In conclusion, <em>the sphere has no net charge.</em>

<h2>f. Answer:</h2>

Here we want to know how the negative charges in the same sphere are redistributed when a positively charged rod is brought near it. Therefore, positive charge on rod  repels positive charges on the sphere, creating  zones of negative and  positive charge as indicated in the second Figure.

7 0
3 years ago
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I need help again sorry!!?
Taya2010 [7]
The answer is C.....
6 0
4 years ago
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statuscvo [17]
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3 0
3 years ago
Calculate the mechanical advantage of a lever that has an input force of 15 N and an output force of 60 N. *
andreev551 [17]

Answer:

4

Explanation:

Mechanical Advantage is given as a ratio of the force a machines gives out to the force that it receives.

Simply put, it is the ratio of output force to input force:

MA = \frac{OF}{IF}

We are given that:

OF = 60 N

IF = 15 N

Hence, the Mechanical Advantage of the lever is:

MA = \frac{60}{15} \\\\\\MA = 4

It is a ratio so it has no unit.

4 0
3 years ago
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