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Ulleksa [173]
3 years ago
7

Calculate the mechanical advantage of a lever that has an input force of 15 N and an output force of 60 N. *

Physics
2 answers:
svp [43]3 years ago
5 0

Answer:

Explanation:

Given that, .

Input effort is 15N

Fi = 15N

Output effort is 60N

Fo = 60N

Then,

Mechanical advantage(M•A) is the ratio of two forces, and it is also referred to has force ratio.

M•A = Output Force / Input Force

M•A = Fo / Fi

M•A = 60 / 15

M•A = 4

The mechanical advantage is 4

andreev551 [17]3 years ago
4 0

Answer:

4

Explanation:

Mechanical Advantage is given as a ratio of the force a machines gives out to the force that it receives.

Simply put, it is the ratio of output force to input force:

MA = \frac{OF}{IF}

We are given that:

OF = 60 N

IF = 15 N

Hence, the Mechanical Advantage of the lever is:

MA = \frac{60}{15} \\\\\\MA = 4

It is a ratio so it has no unit.

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Answer:

positions of motion is the answer as moving is a motion

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1 year ago
A railroad car of mass 2.50*10^4 kg is moving with a speed of 4.00 m/s. It collides and couples with three other coupled railroa
NemiM [27]

Answer:

(a) 2.5 m/s

(b) 37.5 KJ

Explanation:

(a)

From the law of conservation of momentum, Initial momentum=Final momentum

mV_1+3mV_2=(m+3m)V_f=4mV_f

V_1+3V_2=4V_f and making V_f the subject then

V_f=\frac {V_1+3V_2}{4} and since V_1 is initial velocity of car, value given as 4 m/s, V_2 is the initial velocity of the three cars stuck together, value given as 2 m/s and v_f is the final velocity which is unknown. By substitution

V_f=\frac {4+(3\times2)}{4}=2.5 m/s

(b)

Initial kinetic energy is given by

\frac {mV_1^{2}}{2}+\frac {3mV_2^{2}}{2}=\frac {m(V_1^{2}+3V_2^{2}}{2}=\frac {2.5\times 10^{4}(4^{2}+3(2^{2}))}{2}=350\times10^{3} J= 350 KJ

Final kinetic energy is given by

\frac {4mV_f^{2}}{2}=\frac {4\times 2.5\times 10^{4}\times 2.5^{2}}{2}=312.5\times 10^{3} J=312.5 KJ

The energy lost is given by subtracting the final kinetic energy from the initial kinetic energy hence

Energy lost=350-312.5=37.5 KJ

6 0
3 years ago
Read 2 more answers
Use the drop-down menus to identify the parts of the
DochEvi [55]

Answer:

Label A: Battery, Label B: Light or Bulb, Label C: Switch

Explanation:

I got it right.

5 0
3 years ago
Un vas plin cu lichid cântăreşte 175kg. Ceea ce reprezintă de 5 ori masa vasului gol. Ştiind că volumul interior al vasului este
Mariana [72]

a) Density of the liquid: 823.5kg/m^3

b) Weight of the liquid: 1372 N

Explanation:

Translation of the text:

<em>"A full tank with liquid weighs 175kg. Which is 5 times the mass of the empty vessel. Knowing that the inside volume of the vessel is 0.17kl, calculate: </em>

<em>a) the density of the liquid; </em>

<em>b) the weight of the liquid."</em>

a)

We know that the full tank with liquid has a total mass of M = 175 kg. We can write the total mass as

M=m_L + m_V (1)

where

m_L is the mass of the liquid

m_V is the mass of the vessel

We also know that the total mass M is 5 times the mass of the empty vessel, so we have:

M=5m_V\\m_V=\frac{M}{5}=\frac{175}{5}=35 kg

which is the mass of the empty vessel.

Therefore, we can find the mass of the liquid only using (1):

m_L=M-m_V=175-35=140 kg

The density of the liquid is given by

d=\frac{m}{V}

where

m = 140 kg (mass of the liquid)

V = 0.170 kL = 170 L = 0.170 m^3 (volume of the liquid, which is equal to the volume of the vessel)

So we get

d=\frac{140}{0.170}=823.5kg/m^3

b)

The weight of a body is given by

F=mg

where

m is its mass

g is the acceleration due to gravity

For the liquid in this problem, we have

m = 140 kg (mass)

g=9.8 m/s^2 (acceleration due to gravity)

Therefore, its weight is

F=(140)(9.8)=1372 N

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

6 0
3 years ago
A boat sails south with the help of a wind blowing in the direction S36°E with magnitude 300 lb. Find the work done by the wind
goldfiish [28.3K]

Answer:

The work done by the wind as the boat moves 130 ft is (rounded) W= 31,550 ft-lb.

Explanation:

F= 300 lb < -54º

Fsouth= 300 lb * cos(36º)

Fsouth= 242.7 lb

d= 130 ft

W= F*d

W= 31551 ft-lb

6 0
3 years ago
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