All categories

2 years ago

Calculate the mechanical advantage of a lever that has an input force of 15 N and an output force of 60 N. *

Physics

2 answers:

svp [43]2 years ago

5 0

Answer:

Explanation:

Given that, .

Input effort is 15N

Fi = 15N

Output effort is 60N

Fo = 60N

Then,

Mechanical advantage(M•A) is the ratio of two forces, and it is also referred to has force ratio.

M•A = Output Force / Input Force

M•A = Fo / Fi

M•A = 60 / 15

M•A = 4

The mechanical advantage is 4

andreev551 [17]2 years ago

4 0

Answer:

Explanation:

Mechanical Advantage is given as a ratio of the force a machines gives out to the force that it receives.

Simply put, it is the ratio of output force to input force:

$MA = \frac{OF}{IF}$

We are given that:

OF = 60 N

IF = 15 N

Hence, the Mechanical Advantage of the lever is:

$MA = \frac{60}{15} \\\\\\MA = 4$

It is a ratio so it has no unit.

You might be interested in

Using the law of conservation of angular momentum, estimate how fast a collapsed stellar core would spin if its initial spin rat

Nataly_w [17]

Answer:

$\omega_{f} = 1000000\,\frac{rev}{day}$

Explanation:

The law of conservation of angular momentum states that angular momentum remains constant when there is no external moment or forces applied to the system. Let assume that star can be modelled as an sphere, then:

$\frac{2}{5}\cdot M\cdot R_{o}^{2} \cdot \omega_{o} = \frac{2}{5}\cdot M\cdot R_{f}^{2} \cdot \omega_{f}$

The final angular speed is:

$\omega_{f} = \omega_{o}\cdot (\frac{R_{o}}{R_{f}})^{2}$

$\omega_{f} = (1\,\frac{rev}{day} )\cdot (\frac{10000\,km}{10\,km} )^{2}$

$\omega_{f} = 1000000\,\frac{rev}{day}$

3 0

2 years ago

What is the relationship between the temperature of a star and its luminosity?

Sladkaya [172]

The Luminosity of a star is proportional to its Effective Temperature to the 4th power and its Radius squared.

3 0

2 years ago

This is the rate of distance traveled per unit of time, without regard to direction.

svetlana [45]

Speed is the rate of distance traveled per unit of time without regards to direction.

<u>Explanation</u>:

Speed is the pace of separation traveled per unit of time, regardless of direction.

Speed is straightforwardly relative to separate when time is consistent and conversely corresponding to a time when separation is steady. Multiplying one's speed would mean multiplying one's separation went in a given measure of time. Multiplying one's speed would likewise mean splitting the time required to travel a given separation.

4 0

2 years ago

Read 2 more answers

A block moving to the right on a level surface with friction is pulled by an increasing horizontal force also directed to the ri

KengaRu [80]

Answer:

e) True Yes both are constant

Explanation:

Let us propose the solution of the problem before reviewing the statements, we use Newton's second law

F - fr = m a

N- W = 0

N = mg

The equation for the force of friction is

fr = μ N

F - μ mg = m a

F = m (a- μ g)

Now let's review the claims

.a) False. Normal force and friction are constants.

.b) False. Both are constant.

.c) False. Both are constant.

d.) False

e) True Yes both are constant

6 0

2 years ago

Two forces act on a 41-kg object. One force has magnitude 65 N directed 59° clockwise from the positive x-axis, and the other ha

Genrish500 [490]

Answer:

a = 1.41 m/s²

Explanation:

Given that

mass ,m= 41 kg

F₁ = 65 N , θ = 59°

F₂ = 35 N ,θ = 32°

The component of Force F₁

F₁x= F₁cos59° i

F₁x= 65 x cos59° i = 33.47 i

F₁y= - F₁ sin 59° j

F₁y= - 65 x sin 59° j = - 55.71 j

The component of Force F₂

F₂x= F₂ sin 32° i

F₂x= 35 x sin 32° i = 18.54 i

F₂y= F₂ cos 32° j

F₂y= 35 x cos 32° j = 29.68 j

The total force F

F= 33.47 i + 18.54 i - 55.71 j + 29.68 j

F= 52.01 i - 26.03 j

The magnitude of the force F

$F=\sqrt{52.01^2+26.03 ^2}\ N$

F=58.16 N

We know that

F= m a

a= Acceleration

m=mass

58.16 = 41 x a

a = 1.41 m/s²

6 0

2 years ago