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4 years ago

If an object is raised 100m above the ground with the mass of 100kg, how much gravitational potential energy did it gain?

Physics

2 answers:

Grace [21]4 years ago

7 0

Answer:

Explanation:

The equation for gravitational potentional energy is mass x gravitational field strength x change in height.

We are going to assume that g.f.s. is 10 N/kg

mass = 100 kg

change in height = 100

Therefore if we plug these value into the equation we get 100 x 100 x 10 = 100000

solong [7]4 years ago

3 0

Answer:

100,000kgm^2/s^2

I Hope It Helps

Explanation:

$GPE = mgh\\GPE = Gravitational Energy\\m= 100kg\\g = 10m/s^2\\h = 100m\\GPE = 100*10*100\\GPE = 100,000 kg m^2 / s^2$

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Virty [35]

Explanation:

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4 0

3 years ago

A 1,250 W electric motor is connected to a 220 Vrms, 60 Hz source. The power factor is lagging by 0.65. To correct the pf to 0.9

Black_prince [1.1K]

Answer:

$C = 46.891 \mu F$

Explanation:

Given data:

v = 220 rms

power factor = 0.65

P = 1250 W

New power factor is 0.9 lag

we knwo that

$s = \frac{P}{P.F} < COS^{-1} 0.65$

$S = \frac{1250}{0.65} < 49.45$

s = 1923.09 < 49.65^o

s = [1250 + 1461 j] vA

$P.F new = cos [tan^{-1} \frac{Q_{new}}{P}]$

solving for $Q_{new}$

$Q_{new} = P tan [cos^{-1} P.F new]$

$Q_{new} = 1250 [tan[cos^{-1}0.9]]$

$Q_{new} = 605.40 VARS$

$Q_C = Q - Q_{new}$

$Q_C = 1461 - 605.4 = 855.6 vars$

$Q_C = \frac[v_{rms}^2}{xc} =v_{rms}^2 \omega C$

$C = \frac{Q_C}{ v_{rms}^2 \omega}$

$C = \frac{855.6}{220^2 \times 2\pi \times 60}$

$C = 4..689 \times 10^{-5}$ Faraday

$C = 46.891 \mu F$

6 0

4 years ago

Please help<br>What is the angle of the reflected ray in the diagram above?

Elena-2011 [213]

I think a reflected ray should be symmetrical so I believe your answer is 32 degrees

5 0

3 years ago

. Two astronauts are 1.90 m apart in their spaceship. One speaks to the other. The conversation is transmitted to earth via elec

melomori [17]

Answer:

d= 1650 km.

Explanation:

Assuming that sound waves travel along a straight line at a constant speed of 346 m/s, we can find the time needed for the sound to travel the distance of 1.9 m between the astronauts, just applying the definition of average velocity, as follows:

$t = \frac{\Delta x}{v} =\frac{1.9m}{346m/s} = 5.5 msec (1)$

The electromagnetic waves travel in free space at the same speed of light in vacuum ( since light is a electromagnetic wave indeed), i.e., 3*10⁸ m/s.
Applying the same formula than in (1) we can solve for the distance d, as follows:

$d = v*t = 3e8 m/s*5.5e-3s = 1650 km (2)$

3 0

3 years ago

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jeka94

Answer:

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6 0

3 years ago