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Mashcka [7]
3 years ago
13

Find the slope of the line passing through the points (3, -2) and (1, -8).

Mathematics
1 answer:
stiv31 [10]3 years ago
4 0

Answer: your slope would be 3

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To finish a certain job in 8 days, 6 workers are needed. If it is required to finish the same job in 2 days advance, how many wo
kotykmax [81]

Answer:  96 workers

Step-by-step explanation:

First you multiply 8 and 6 then by 2.

8 x 6= 48

48 x 2= 96

96 workers to help the business

4 0
3 years ago
Please hurry i need these fast
ExtremeBDS [4]

Answer:

95

Step-by-step explanation:

you first find out the angles mn and mt.

Since ns and ms are the same, we know ms is 35 degrees.

mt is 50, so we subtract 50 and 35 from 180, which is the degree of m.

so the answer is 95 degrees.

5 0
3 years ago
Read 2 more answers
Find all critical points of the given plane autonomous system. (Enter your answers as a comma-separated list.) x′ = x 12 − x − 1
Andru [333]

Answer:

the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

Step-by-step explanation:

To consider the autonomous system

x' =x (12 -x - \dfrac{1}{2})

y' = y( 20 -y - x)

The critical points of the above system can be derived by replacing x' = o and y' = 0.

i.e.

x' =x (12 -x - \dfrac{y}{2}) = 0

\dfrac{x}{2} (24 -2x - y) = 0

x = 0 or 24 - 2x - y = 0     ----- (1)

Also

y' = y( 20-y-x) = 0

y( 20 -y - x) = 0

y = 0 or 20 - y - x = 0  -----   (2)

By solving (1) and (2);

we get x = 4 and y = 16

Suppose x = 0 from (2)

y = 20

Also;

if y = 0 from (1)

x = 12

Thus, the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

6 0
2 years ago
Geometry
g100num [7]
A=27 \ cm^2 \\ \\ d_{1}=3x , \ \ d_{2} = 2x \\ \\ S=\frac{1}{2}\cdot d_{1}\cdot d_{2}\\ \\27 = \frac{1}{2}\cdot 3x \cdot 2x \\ \\ 3x^2 = 27 \ \ /:3

x^2 = 9 \\ \\3x=x=\sqrt{9}\\ \\x=3 \ cm \\ \\ d_{1}=3x = 3*3 =9 \ cm \\ \\d_{2}=2x=2*3 = 6 \ cm \\ \\ Answer : \\ The \ length \  of \ the \ diagonal  \ is:  \ d_{1}= 9 \ cm \ and \ d_{2}=  6 \ cm

7 0
3 years ago
In ΔJKL, the measure of ∠L=90°, JL = 24, LK = 7, and KJ = 25. What is the value of the sine of ∠K to the nearest hundredth?
podryga [215]

<u>Given</u>:

Given that JKL is a right triangle.

The measure of ∠L is 90°

The length of JL = 24, LK = 7, and KJ = 25.

We need to determine the value of sine of ∠K.

<u>Value of sin ∠K:</u>

The value of sin ∠K can be determine using the trigonometric ratio.

Thus, we have;

sin \ \theta=\frac{opp}{hyp}

Substituting \theta=K, the side opposite to angle K is JL and the hypotenuse is JK

Thus, we have;

sin \ K=\frac{JL}{JK}

Substituting JL = 24 and JK = 25, we get;

sin \ K=\frac{24}{25}

Simplifying, we get;

sin \ K=0.96

     K=sin^{-1}(0.96)

     K=73.74^{\circ}

Thus, the measure of sine of ∠K is 73.74°

6 0
3 years ago
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