Answer and Step-by-step explanation:
Given that probability of you winning each game = 0.68
And probability of you winning next game = 0.81
Your friend's chance of winning/you losing would be = 1-0.68= 0.32
also his chance of winning next game = 0.73
To find probability that you would win the series given that you need to win two games to win the series
= probability that you win first game and second game+ probability that you win first game, lose second game and win third game + probability that you lose first game, win second game and win third game
= 0.68*0.81+0.68*0.32*0.68+0.32*0.68*0.81
=0.8750
Therefore probability that you would win the series = 0.8750
Note: here we found the probability of winning by adding(or) up the three possible combinations that would result in a win
Yes I sure did hang the picture what about it
Solve the equation of the function for n.
a(n) = 3n - 20
a = 3n - 20
a + 20 = 3n
(a + 20)/3 = n
n = (a + 20)/3
n(a) = (a + 20)/3
H = 2s + 75 is the answer
Answer:
b
Step-by-step explanation:
is the proper answer
