Given:
The point, (4, -3)
The line,

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:
The slope of the line is,

Since the given line is parallel to the new line, so the slope will be same for the both.
Using the point-slope formula,

Substitute the point and slope we get,

Hence, the equation in slope-intercept form for the line is,
Answer:
um I don't understand it pls be more specific and I will help
quadratic formula:
x = <u>-b ± √(b² - 4ac)</u>
2a
7x² - x = 7
subtract 7 from both sides:
7x² - x - 7 = 0
plug values into the quadratic formula:
x = <u>-(-1) ± √((-1)²- 4(7)(-7))</u>
2(7)
simplify:
x = <u>1 ± √(197)</u>
14