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3 years ago

What is the approximate area?

Mathematics

2 answers:

Karolina [17]3 years ago

8 0

Answer:

71.76 cm^2

Step-by-step explanation:

The composite figure is made up of a rectangle with a missing half circle and a triangle.

area = area of rectangle + area of triangle - area of half circle

For the circle, radius = r = diameter/2 = 7 cm/2 = 3.5 cm.

area = LW + bh/2 - (pi)r^2/2

area = 10 cm * 7 cm + 7 cm * 6 cm/2 + (3.14)(3.5 cm)^2/2

area = 70 cm^2 + 21 cm^2 - 19.24 cm^2

area = 71.77 cm^2

Answer: 71.76 cm^2

valentina_108 [34]3 years ago

4 0

Answer:

71.77cm

Step-by-step explanation:

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Can anyone help me on the last question?

Novosadov [1.4K]

Answer:

Step-by-step explanation:

A' is everything what is not A

So:

A' = {9, 10, 11, 12, 13, 15, 16}

Number of ways it can happen: |A'| = 7

Total number of outcomes: |Ω| = 10

Probability of an event happening:

$\bold{P(A')=\dfrac{|A'|}{|\Omega|}=\dfrac7{10}=0.7}$

8 0

3 years ago

1. - x + 5y =-23 4x - y = 16

Contact [7]

6y=5x=39
Have a good day

8 0

3 years ago

Read 2 more answers

Need some help working these out

s2008m [1.1K]

Answers:

Problem 1) 40 degrees
Problem 2) 84 degrees
Problem 3) 110 degrees

===============================================

Explanation:

For these questions, we'll use the inscribed angle theorem. This says that the inscribed angle is half the measure of the arc it cuts off. An inscribed angle is one where the vertex of the angle lies on the circle, as problem 1 indicates.

For problem 1, the arc measure is 80 degrees, so half that is 40. This is the measure of the unknown inscribed angle.

Problem 2 will have us work in reverse to double the inscribed angle 42 to get 84.

-------------------

For problem 3, we need to determine angle DEP. But first, we'll need Thales Theorem which is a special case of the inscribed angle theorem. This theorem states that if you have a semicircle, then any inscribed angle will always be 90 degrees. This is a handy way to form 90 degree angles if all you have is a compass and straightedge.

This all means that angle DEF is a right angle and 90 degrees.

So,

(angle DEP) + (angle PEF) = angle DEF

(angle DEP) + (35) = 90

angle DEP = 90 - 35

angle DEP = 55

The inscribed angle DEP cuts off the arc we want to find. Using the inscribed angle theorem, we double 55 to get 110 which is the measure of minor arc FD.

3 0

3 years ago

A sphere and a cylinder have the same radius and height. The volume of the cylinder is . Amie found the volume of the sphere. He

dezoksy [38]

Amie's error while measuring the volume of a sphere is that <u>Amie should have multiplied 54 by 2/3</u>. Thus, the <u>first option</u> is the right choice.

In the question, we are given that a sphere and a cylinder have the same radius and height.

We assume the radius of the sphere to be r, and its height to be h.

Now, the height of a sphere is its diameter, which is twice the radius.

Thus, the height of the sphere, h = 2r

Given that the sphere and the cylinder have the same radius and height, the radius of the cylinder is r, and its height is 2r.

The volume of a sphere is given by the formula, V = (4/3)πr³, where V is its volume, and r is its radius.

Thus, the volume of the given sphere using the formula is (4/3)πr³.

The volume of a cylinder is given by the formula, V = πr²h, where V is its volume, r is its radius, and h is its height.

Thus, the volume of the given cylinder using the formula is πr²(2r) = 2πr³.

Now, to compare the two volumes we take their ratios, as

Volume of the sphere/Volume of the cylinder

= {(4/3)πr³}/{2πr³}

= 2/3.

Thus, the volume of the sphere/the volume of the cylinder = 2/3,

or, the volume of the sphere = (2/3)*the volume of the cylinder.

Given the volume of the cylinder to be 54 m³, Amie should have multiplied 54 by 2/3 instead of adding the two.

Thus, Amie's error while measuring the volume of a sphere is that <u>Amie should have multiplied 54 by 2/3</u>. Thus, the <u>first option</u> is the right choice.

Learn more about volumes at

brainly.com/question/12398192

#SPJ4

For the complete question, refer to the attachment.