$820.02
Step-by-step explanation:
Since the Taylor family had cash receipts of $876.16 and their excess of cash receipts above cash payments was $56.14.
The total cash payments for the month will be calculated as:
= $876.16 - $56.14
= $820.02
Answer:
99
Step-by-step explanation:
The mean = 90 days
standard deviation = 20 days
P(Z < z) = 68 %
getting the value of z-score from the standard normal table of 0.68
z = 0.47
P(Z < 0.47) = 0.47 * 20 + 90 = 99
Answer: 7.5
Step-by-step explanation:
use pythagorean theorem
13^2 + b^2 = 15^2
- 13^2
b^2 = 56 - square root
= 7.5
Answer:
each student gets 2 bars and a quarter of one (2.25 or 2 1/4)
Step-by-step explanation:
Answer:

Step-by-step explanation:
Hello, first of all, we will check if we can factorise the polynomials.




Now, let's compute the product.

So the correct answer is the first one.
Thank you.