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gregori [183]
4 years ago
7

Difference in the following polynomials (6x^3 - 2x^2 + 4) -(2x^3 + 4x^2 - 5)

Mathematics
1 answer:
Colt1911 [192]4 years ago
6 0

\bold{[ \ Answer \ ]}

\boxed{\bold{4x^3-6x^2+9}}

\bold{[ \ Explanation \ ]}

  • \bold{Find \ Difference: \ \left(6x^3\:-\:2x^2\:+\:4\right)-\left(2x^3\:+\:4x^2\:-\:5\right)}

\bold{-----------------------}

  • \bold{Remove \ Parenthesis}

\bold{6x^3-2x^2+4-\left(2x^3+4x^2-5\right)}

  • \bold{Remove \ Parenthesis \ / \ Simplify}

\bold{-\left(2x^3+4x^2-5\right): \ -2x^3-4x^2+5}

  • \bold{Rewrite}

\bold{6x^3-2x^2+4-2x^3-4x^2+5}

  • \bold{[Simplify \ 6x^3-2x^2+4-2x^3-4x^2+5] \ 4x^3-6x^2+9}

\bold{4x^3-6x^2+9}

\boxed{\bold{[] \ Eclipsed \ []}}

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3 years ago
a sinusoid always function has an amplitude of 3, a frequency of 1/8pi, and a midline at 2. Which of the following equations sat
Katen [24]

Answer:

The correct option is;

f(x) = 3·sin x/8·π + 2

Step-by-step explanation:

The given parameters for the sinusoidal function are;

Amplitude of oscillation = 3

Frequency of oscillation = 1/8·π

Midline of oscillation= 2

The general form of sinusoidal equation is y = A·sin(B(x - C)) + D

Where;

A = The amplitude

B = The frequency

C = The horizontal shift

D = The midline or vertical shift

Substituting the given values into the general form of sinusoidal equation, we have;

f(x) = y =  3·sin(1/8·π(x - 0)) + 2 = 3·sin(x/8·π) + 2

Which gives;

f(x) = 3·sin(x/8·π) + 2.

5 0
4 years ago
Which of these numbers is greater than 2.25 but less than 1? Is it 1 or 1.5 or 0 or 2.5
Sloan [31]

Answer:

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5 0
3 years ago
Point G is the centroid of triangle ABC. AG = (5x+4) units and GF= (3x-1) units. What is A F?
Vika [28.1K]
<span>Because G is the centroid of the triangle, therefore AG = 2GF
That is, 5x + 4 = 2(3x - 1)
5x + 4 = 6x - 2
4 + 2 = 6x - 5x
6 = x
Therefore AG = 5*6 + 4 = 34
GF = 3*6 - 1 = 17
A.F = AG + GF = 34 + 17 = 51
Answer: 51</span>
6 0
3 years ago
Read 2 more answers
if one Circle has a diameter of 10 cm and a second Circle has a diameter of 20 cm what is the ratio of the area of the larger ci
Oxana [17]
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The radius of the larger circle with diameter 20 cm.is 10 cm.

Area of larger circle : Area of smaller circle

Area of larger circle = 100π.

Area of smaller circle = 25π.

Ratio = 100π : 25π or 100π/25π.

7 0
3 years ago
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